'How to go to next line after every row in a 2D array?

So I need to come up with something like this: It's a layout of seats on an airplane.

1 A B C D

2 A B C D

3 A B C D

4 A B C D

5 A B C D

6 A B C D

7 A B C D

But instead my code prints this:

ABCD

ABCABCD

ABCABCD

ABCABCD

ABC

This is my code, any help would be really appreciated. I just started working with arrays

#include <iostream>

using namespace std;

int main ()
{
     char airplane[7][4] = {{'A', 'B', 'C', 'D'},
                             {'A', 'B', 'C', 'D'},
                             {'A', 'B', 'C', 'D'},
                             {'A', 'B', 'C', 'D'},
                             {'A', 'B', 'C', 'D'},
                             {'A', 'B', 'C', 'D'},
                             {'A', 'B', 'C', 'D'}};

     for (int i=0; i<4; i++)
     {

            for (int j=0; j<7; j++)
            {
                 cout<<airplane[i][j];
                 if (airplane[i][j]=='D')
                 {
                     cout<<endl;
                 }
            }
     }

     system ("PAUSE");
     return 0;
}
c++arrays


Solution 1:[1]

Here the code :

 #include <iostream>

    using namespace std;

    int main ()
    {
         char airplane[7][4] = {{'A', 'B', 'C', 'D'},
                                 {'A', 'B', 'C', 'D'},
                                 {'A', 'B', 'C', 'D'},
                                 {'A', 'B', 'C', 'D'},
                                 {'A', 'B', 'C', 'D'},
                                 {'A', 'B', 'C', 'D'},
                                 {'A', 'B', 'C', 'D'}};

         for (int i=0; i<7; i++)
         {
             cout << i+1;
                for (int j=0; j<4; j++)
                {
                     cout<<airplane[i][j];
                     if (airplane[i][j]=='D')
                     {
                         cout<<endl;
                     }
                }
         }

         system ("PAUSE");
         return 0;
    }

Solution 2:[2]

Change the for loop in this fashion

for (int i=0; i<7; i++)
     {
            cout<<i+1;
            for (int j=0; j<4; j++)
            {
                cout<<' ';
                 cout<<airplane[i][j];                

            }
            cout<<endl;
     }

Solution 3:[3]

Try running your outer loop for 7 times and inner loop for 4 times. Include cout<

And by the way the code given by Bui Akinori is buggy for if you change the number of seats in each row to five.

Solution 4:[4]

try this..:-->

#include <iostream>

using namespace std;

int main ()
{
  char airplane[7][4] = {{'A', 'B', 'C', 'D'},
                         {'A', 'B', 'C', 'D'},
                         {'A', 'B', 'C', 'D'},
                         {'A', 'B', 'C', 'D'},
                         {'A', 'B', 'C', 'D'},
                         {'A', 'B', 'C', 'D'},
                         {'A', 'B', 'C', 'D'}};

 for (int i=0; i<7; i++)       //Row
 {
        cout<<i+1;
        for (int j=0; j<4; j++)    //Column
        {
             cout<<airplane[i][j];
             cout<<" "; 
        }
     cout<<endl;
 }

 system ("PAUSE");
 return 0;
}

Sources

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Source: Stack Overflow

Solution Source
Solution 1 ??c Bùi
Solution 2 kjana83
Solution 3 10101010
Solution 4

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