How to process a string as a file to contruct a ZipFile object?

Question

I am currently pulling data from a database with blobs. I retrieve the blob from the database, but I need to parse the text. the ZipFile class takes in files not strings, so what would be a good way to solve this?

import zipfile

data= request.files["file"].read() #this is just binary data
zipfile.ZipFile(data)

Answer 1

use io.BytesIO or io.StringIO
essentially u just need file-like interface