'How to read a properties files and use the values in project Gradle script?
I am working on a Gradle script where I need to read the local.properties
file and use the values in the properties file in build.gradle
. I am doing it in the below manner. I ran the below script and it is now throwing an error, but it is also not doing anything like creating, deleting, and copying the file. I tried to print the value of the variable and it is showing the correct value.
Can someone let me know if this is the correct way to do this? I think the other way is to define everything in the gradle.properties
and use it in the build.gradle
. Can someone let me know how could I access the properties in build.gradle
from build.properties
?
build.gradle
file:
apply plugin: 'java'
// Set the group for publishing
group = 'com.true.test'
/**
* Initializing GAVC settings
*/
def buildProperties = new Properties()
file("version.properties").withInputStream {
stream -> buildProperties.load(stream)
}
// If jenkins build, add the jenkins build version to the version. Else add snapshot version to the version.
def env = System.getenv()
if (env["BUILD_NUMBER"]) buildProperties.test+= ".${env["BUILD_NUMBER"]}"
version = buildProperties.test
println "${version}"
// Name is set in the settings.gradle file
group = "com.true.test"
version = buildProperties.test
println "Building ${project.group}:${project.name}:${project.version}"
Properties properties = new Properties()
properties.load(project.file('build.properties').newDataInputStream())
def folderDir = properties.getProperty('build.dir')
def configDir = properties.getProperty('config.dir')
def baseDir = properties.getProperty('base.dir')
def logDir = properties.getProperty('log.dir')
def deployDir = properties.getProperty('deploy.dir')
def testsDir = properties.getProperty('tests.dir')
def packageDir = properties.getProperty('package.dir')
def wrapperDir = properties.getProperty('wrapper.dir')
sourceCompatibility = 1.7
compileJava.options.encoding = 'UTF-8'
repositories {
maven { url "http://arti.oven.c:9000/release" }
}
task swipe(type: Delete) {
println "Delete $projectDir/${folderDir}"
delete "$projectDir/$folderDir"
delete "$projectDir/$logDir"
delete "$projectDir/$deployDir"
delete "$projectDir/$packageDir"
delete "$projectDir/$testsDir"
mkdir("$projectDir/${folderDir}")
mkdir("projectDir/${logDir}")
mkdir("projectDir/${deployDir}")
mkdir("projectDir/${packageDir}")
mkdir("projectDir/${testsDir}")
}
task prepConfigs(type: Copy, overwrite:true, dependsOn: swipe) {
println "The name of ${projectDir}/${folderDir} and ${projectDir}/${configDir}"
from('${projectDir}/${folderDir}')
into('${projectDir}/$configDir}')
include('*.xml')
}
build.properties
file:
# -----------------------------------------------------------------
# General Settings
# -----------------------------------------------------------------
application.name = Admin
project.name = Hello Cool
# -----------------------------------------------------------------
# ant build directories
# -----------------------------------------------------------------
sandbox.dir = ${projectDir}/../..
reno.root.dir=${sandbox.dir}/Reno
ant.dir = ${projectDir}/ant
build.dir = ${ant.dir}/build
log.dir = ${ant.dir}/logs
config.dir = ${ant.dir}/configs
deploy.dir = ${ant.dir}/deploy
static.dir = ${ant.dir}/static
package.dir = ${ant.dir}/package
tests.dir = ${ant.dir}/tests
tests.logs.dir = ${tests.dir}/logs
external.dir = ${sandbox.dir}/FlexCommon/External
external.lib.dir = ${external.dir}/libs
Solution 1:[1]
If using the default gradle.properties
file, you can access the properties directly from within your build.gradle
file:
gradle.properties
:
applicationName=Admin
projectName=Hello Cool
build.gradle
:
task printProps {
doFirst {
println applicationName
println projectName
}
}
If you need to access a custom file, or access properties which include .
in them (as it appears you need to do), you can do the following in your build.gradle
file:
def props = new Properties()
file("build.properties").withInputStream { props.load(it) }
task printProps {
doFirst {
println props.getProperty("application.name")
println props.getProperty("project.name")
}
}
Take a look at this section of the Gradle documentation for more information.
Edit
If you'd like to dynamically set up some of these properties (as mentioned in a comment below), you can create a properties.gradle
file (the name isn't important) and require it in your build.gradle
script.
properties.gradle
:
ext {
subPath = "some/sub/directory"
fullPath = "$projectDir/$subPath"
}
build.gradle
apply from: 'properties.gradle'
// prints the full expanded path
println fullPath
Solution 2:[2]
We can use a separate file (config.groovy
in my case) to abstract out all the configuration.
In this example, we're using three environments viz.,
- dev
- test
- prod
which has properties serverName, serverPort and resources. Here we're expecting that the third property resources may be same in multiple environments and so we've abstracted out that logic and overridden in the specific environment wherever necessary:
config.groovy
resources {
serverName = 'localhost'
serverPort = '8090'
}
environments {
dev {
serverName = 'http://localhost'
serverPort = '8080'
}
test {
serverName = 'http://www.testserver.com'
serverPort = '5211'
resources {
serverName = 'resources.testserver.com'
}
}
prod {
serverName = 'http://www.productionserver.com'
serverPort = '80'
resources {
serverName = 'resources.productionserver.com'
serverPort = '80'
}
}
}
Once the properties file is ready, we can use the following in build.gradle
to load these settings:
build.gradle
loadProperties()
def loadProperties() {
def environment = hasProperty('env') ? env : 'dev'
println "Current Environment: " + environment
def configFile = file('config.groovy')
def config = new ConfigSlurper(environment).parse(configFile.toURL())
project.ext.config = config
}
task printProperties {
println "serverName: $config.serverName"
println "serverPort: $config.serverPort"
println "resources.serverName: $config.resources.serverName"
println "resources.serverPort: $config.resources.serverPort"
}
Let's run these with different set of inputs:
gradle -q printProperties
Current Environment: dev serverName: http://localhost serverPort: 8080 resources.serverName: localhost resources.serverPort: 8090
gradle -q -Penv=dev printProperties
Current Environment: dev serverName: http://localhost serverPort: 8080 resources.serverName: localhost resources.serverPort: 8090
gradle -q -Penv=test printProperties
Current Environment: test serverName: http://www.testserver.com serverPort: 5211 resources.serverName: resources.testserver.com resources.serverPort: 8090
gradle -q -Penv=prod printProperties
Current Environment: prod serverName: http://www.productionserver.com serverPort: 80 resources.serverName: resources.productionserver.com resources.serverPort: 80
Solution 3:[3]
Another way... in build.gradle:
Add :
classpath 'org.flywaydb:flyway-gradle-plugin:3.1'
And this :
def props = new Properties()
file("src/main/resources/application.properties").withInputStream { props.load(it) }
apply plugin: 'flyway'
flyway {
url = props.getProperty("spring.datasource.url")
user = props.getProperty("spring.datasource.username")
password = props.getProperty("spring.datasource.password")
schemas = ['db_example']
}
Solution 4:[4]
This is for Kotlin DSL (build.gradle.kts):
import java.util.*
// ...
val properties = Properties().apply {
load(rootProject.file("my-local.properties").reader())
}
val prop = properties["myPropName"]
In Android projects (when applying the android plugin) you can also do this:
import com.android.build.gradle.internal.cxx.configure.gradleLocalProperties
// ...
val properties = gradleLocalProperties(rootDir)
val prop = properties["propName"]
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | mkobit |
Solution 2 | |
Solution 3 | Bruno |
Solution 4 |