'How to set spring dispatcherServlet path?

I use application.properties file to set DispatcherServlet path:

server.servlet.path=/api/

When I go to url /api/, I get this exception:

Caused by: org.springframework.beans.NotReadablePropertyException: Invalid property 'servlet[path]' of bean class [org.springframework.boot.autoconfigure.web.ServerProperties]: Bean property 'servlet[path]' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter?
    at org.springframework.beans.BeanWrapperImpl.getPropertyValue(BeanWrapperImpl.java:731)
    at org.springframework.beans.BeanWrapperImpl.setPropertyValue(BeanWrapperImpl.java:948)
    ... 59 common frames omitted

How to set DispatcherServlet path?

javaspring


Solution 1:[1]

You always can look over the Spring properties appendix to find a property you want:

server.servlet-path=/ # Path of the main dispatcher servlet.

Solution 2:[2]

According to the application.properties docs:

server.servlet-path=/ # Path of the main dispatcher servlet.

The correct key is server.servlet-path, notice the -.

Solution 3:[3]

It's spring.mvc.servlet.path now (2.3.x). Let's see when it changes again :)

Solution 4:[4]

Use spring.mvc.servlet.path=/api since server.servlet.path got deprecated

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Andrew Tobilko
Solution 2
Solution 3 Hans Westerbeek
Solution 4 Eduardo Vilaça

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