'How to use view modifiers only available for iOS 14+ with deployment target of iOS 13
How can you add a view modifier to a view when it's only available on iOS 14 but your app is available for iOS 13?
For an example, textCase(_)
. Section headers in iOS 14 are uppercase so to use the case of your header text you should set .textCase(.none)
on your Text
, but this didn't exist until iOS 14.
Section(header:
Text("Header")
.textCase(.none) //FIXME: 'textCase' is only available in iOS 14.0 or newer
.font(.system(size: 14, weight: .bold))
.foregroundColor(.secondary)
.padding(.top, 50)
)
Xcode offers some suggestions:
- Add if #available version check
- Add @available attribute
If you use the #available version check, it wraps all of that scoped code with #available, so you'd have to duplicate all of that to add that one line of code. If you use @available you have to duplicate the entire body property or entire struct.
I considered creating my own ViewModifier that would only apply it if iOS 14 but that gives this dreaded error:
Function declares an opaque return type, but the return statements in its body do not have matching underlying types
struct CompatibleTextCaseModifier: ViewModifier {
func body(content: Content) -> some View {
if #available(iOS 14.0, *) {
return content
.textCase(.none)
} else {
return content
}
}
}
Solution 1:[1]
Mark body
as @ViewBuilder
- this will allow track internal different return types automatically, and remove return
because explicit return disables view builder wrapper.
So here is fixed variant
struct CompatibleTextCaseModifier: ViewModifier {
@ViewBuilder
func body(content: Content) -> some View {
if #available(iOS 14.0, *) {
content
.textCase(.none)
} else {
content
}
}
}
and usage
Section(header:
Text("Header")
.modifier(CompatibleTextCaseModifier())
.font(.system(size: 14, weight: .bold))
.foregroundColor(.secondary)
.padding(.top, 50)
) {
Text("test")
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 |