'Is it possible to detect what type of Default Asset is selected in Unity?

i'm trying to make a custom editor and i was wondering if there's any way to detect what exact type is an asset when GetType() returns UnityEditor.DefaultAsset.

I can detect most of the basic items(Like script, scene, shader, gameobject) but i haven't been able to determine what type is a DefaultAsset. For folders I use the IsValidFolder method, but i don't know if there's a way to get more information for other objects, like a .DLL

This is actually my code:

if (Selection.activeObject == null) return;
switch (Selection.activeObject.GetType().Name)      
{
     case "SceneAsset":
          //IsAScene
     break;
     case "DefaultAsset":
          if (AssetDatabase.IsValidFolder(AssetDatabase.GetAssetPath(Selection.activeObject)))
          //IsAFolder
          else
          //UnknownItem
     break;
     case "MonoScript":
          //IsAScript
     break;
     case "GameObject":
          //IsAGameObject
          if (PrefabUtility.GetPrefabAssetType(Selection.activeGameObject) != PrefabAssetType.NotAPrefab)
               //IsAPrefab
     break;
     case "Shader":
          //IsAShader
     break;
     case "AudioMixerController":
          //IsAnAudioMixer
     break;
     default:     
     //Other
     break;
}
c++sharpunity3d


Solution 1:[1]

There is no general method to get type of DefaultAsset in Unity (yet).

You have to use specific code to detect a specific type.

To detect dll files you can check its extension or importer.

var path = AssetDatabase.GetAssetPath(Selection.activeObject);

var extension = Path.GetExtension(path).ToLowerInvariant();
if(extension == ".dll" || extension == ".so"){}

var importer = AssetImporter.GetAtPath(path) as PluginImporter;
if(importer){}

Solution 2:[2]

Try something like:

if (Selection.activeObject.GetType() == typeof(DefaultAsset))
{
    // ...
}

I'll leave it to you to adopt it into your switch statement. Also as mentioned, don't use magic strings. Use typeof instead.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 shingo
Solution 2 MickyD

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