Is there a way to accept only the integer values after dividing a list?

Question

# Creating List of integers
List = [112, 966, 483, 807, 112, 693, 507, 712, 738, 605, 923, 112, 966, 679, 992, 29, 782, 780, 353, 392]

print("\nList of numbers: ")

print(List)

# Create Divide variable
myInt = 13

#List values divided by 13
newList = [x / myInt for x in List]

print("\nList Divided by 13")

print (newList)

I'm trying to make a new list now that is only of the sum of the division from my listed newList but i'm want only to keep the integers, How would I filter it out?

Or I guess what might be easier, if just listing how many numbers total can be divided by myInt and then output it as an integer?

Answer 1

You can use the modulo operator. someNum % yourInt will not give a remainder if it is divisible, therefore it will return 0. you can use that to filter.

if a % myInt == 0:
    # add to list 

you can find more info here: https://www.geeksforgeeks.org/what-is-a-modulo-operator-in-python/ ( or just searching the modulo operator )

Answer 2

You'll need to check your newList value by using if in list

newList = [int(x / myInt) for x in List if x/myInt % 1 == 0 ]

The result will be [39, 71, 60]

Or you want each numbers integer part you can use

newList = [x // myInt for x in List ]

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