Is there a way to get corresponding values of indexes within keys in a dictionary?

Question

So let's say I have a dictionary for object detections:

dict = {'x1y1coords': [(124, 101), (22, 104)], 'objecttype': [1, 2]}

is there a way that I can easily extract the first value under the list which is under the key value x1y1coords? Just to show what I have in mind:

print((dict['x1y1coords'])[0])

something like this (just to further explain what I had in mind). It's like getting the index of a key index of a dictionary.

And also, it is quite related to this topic, so I don't think I need to create another question (but you can advise me if you think this question needs to be discussed as another problem), I would also like to compare the values of that [x] from ['x1y1coords] to the values of [x] from ['objecttype']. By using my sample code (the one within the print function):

if (dict['objecttype'])[x] == 2:
     p1, p2 = (dict['objecttype'])[x]

Answer 1

Yes, you can absolutely do exactly that:

>>> d = {'x1y1coords': [(124, 101), (22, 104)], 'objecttype': [1, 2]}
>>> d['x1y1coords']
[(124, 101), (22, 104)]
>>> d['x1y1coords'][0]
(124, 101)

If you wanted to assign those values to x and y you could do:

>>> x, y = d['x1y1coords'][0]
>>> x
124
>>> y
101

If you wanted to do something with all the x, y values in the list, instead of just the first one ([0]) you might use a for loop:

>>> for x, y in d['x1y1coords']:
...     print(f"x: {x}\ty: {y}")
...
x: 124  y: 101
x: 22   y: 104