'Javascript check if url param exists
I'm running an A/B test to see if showing more items is better for conversion. But it seems that the code sometimes causes errors.. But I can't find any errors and don't know when they occur.
In my test I check whether the url param IC exists and if it doesn't exists I will add this.
This is my code:
function checkIfAlreadyPaginated()
{
var field = 'IC';
var url = window.location.href;
if(url.indexOf('?' + field + '=') != -1)
return true;
else if(url.indexOf('&' + field + '=') != -1)
return true;
return false;
}
function insertParam(key, value) {
key = encodeURIComponent (key); value = encodeURIComponent (value);
var kvp = document.location.search.substr(1).split('&');
if (kvp == '') {
return '?' + key + '=' + value;
}
else {
var i = kvp.length; var x; while (i--) {
x = kvp[i].split('=');
if (x[0] == key) {
x[1] = value;
kvp[i] = x.join('=');
break;
}
}
if (i < 0) { kvp[kvp.length] = [key, value].join('='); }
return '?'+kvp.join('&');
}
}
var itemsPerPage = 48;
if(!checkIfAlreadyPaginated())
{
document.location.search = insertParam('IC', itemsPerPage);
}
Does someone spot possible issues? I'm running the test via VWO.com.
Solution 1:[1]
If there is a Javascript error you should see it in the browser console and share it with us.
In any case, I would do it by creating a JS Object first. I find it easier to work with.
In the following code I added the option to do the checking for multiple params of the querystring. If you only need to check the IC you can simplify it a bit. I tested it on a blank test.html.
<script type="text/javascript">
// get the current params of the querystring
var querystringItems = document.location.search.substr(1).split('&');
// create an object
var querystringObject = {};
for(i=0;i<querystringItems.length;++i) {
param = querystringItems[i].split('=');
querystringObject[param[0]] = param[1];
}
// Define the keys to be searched for and their default value when they are not present
var requiredKeys = {"IC":48, "test": "me"};
// Do the checking on the querystringObject for each requiredKeys
var doreload = false;
for (var key in requiredKeys) {
if (typeof querystringObject[key] == 'undefined') {
doreload = true;
// Create the missing parameter and assign the default value
querystringObject[key] = requiredKeys[key];
}
}
// If any of the requiredKeys was missing ...
if (doreload) {
// rebuild the querystring
var querystring = '?';
for (var key in querystringObject) {
querystring+=key+'='+querystringObject[key]+'&';
}
querystring=querystring.substr(0,querystring.length-1);
// reload page
document.location.search = querystring;
}
// assign the values to javascript variables (assuming you had it like this because you needed it)
var itemsPerPage = querystringObject.IC;
</script>
Solution 2:[2]
Here is an example to check this:
//get URL params into string:
paramStr = window.location.substring(window.location.indexOf('?'), window.location.length;
//turn string into array
paramArray = paramStr.split('&');
//prepare final array of params
params = {};
//prepare the index of IC parameter
icLoc = -1; //this is negative 1 so that you know if it was found or not
//for each item in array
for(var i in paramArray){
//push its name and value to the final array
params.push(paramArray[i].split('='));
//if the parameter name is IC, output its location in array
if(params[i][0] === 'IC'){
icLoc = i;
}
}
If IC is not found, icLoc will be -1
.
If it is found, the value of IC in the URL parameters is params[icLoc][1]
Example result for query string
?foo=bar&code=cool&IC=HelloWorld
:
params = {'foo': 'bar', 'code': 'cool', 'IC': 'HelloWorld'}
icLoc = 2
Example for query string
?foo=bar&code=cool
:
params = {'foo': 'bar', 'code': 'cool'}
icLoc = -1
Solution 3:[3]
Here id is the param I'm using for a test. Pass the argument which you want to check whether it exists or not.
function queryParamExistUrl(param = '') {
if (new URLSearchParams(window.location.search).get(param) != null)
return true
return false
}
console.log(queryParamExistUrl('id'))
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | MineAndCraft12 |
Solution 3 | Bairavan |