'Laravel excel maatwebsite 3.1 import, date column in excel cell returns as unknown format number. How to solve this?
By using Maatwebsite/Laravel-Excel version 3.1 to import excel sheet, here I faced an issue date time column of the excel sheet returns unknown number. How to solve this? Example : Consider Cell value "29/07/1989" and returns as "32178" when import.
Solution 1:[1]
The numbers come from excel itself, dates stored in excel as numeric values. http://www.cpearson.com/excel/datetime.htm
For Laravel framework 5.6 and maatwebsite/excel package version 3.1, to convert date from excel numbers to normal date format, this function
PhpOffice\PhpSpreadsheet\Shared\Date::excelToDateTimeObject($dateFromExcel)
can be used. It accepts integer(excel date) and returns DateTime object.More information can be found here https://github.com/Maatwebsite/Laravel-Excel/issues/1832
From this answer: https://stackoverflow.com/a/55139981/9133724
Solution 2:[2]
Solved! This is the code I used to solve my problem:
Carbon\Carbon::instance(\PhpOffice\PhpSpreadsheet\Shared\Date::excelToDateTimeObject($value));
Solution 3:[3]
I tried the above solution but always get stuck with non-numeric value error
I manage to solve this using
$date = intval($row['value']);
\PhpOffice\PhpSpreadsheet\Shared\Date::excelToDateTimeObject($date)->format('d/m/Y')
Solution 4:[4]
Based on Skyrem Brilliant
's @skyrem-brilliant answer, I solved it this way:
<?php
//...
class YourExcelImport implements OnEachRow, WithValidation, WithHeadingRow
{
// ...
/**
* Tweak the data slightly before sending it to the validator
* @param $data
* @param $index
* @return mixed
*/
public function prepareForValidation($data, $index)
{
//Fix that Excel's numeric date (counting in days since 1900-01-01)
$data['your_date_column'] = \PhpOffice\PhpSpreadsheet\Shared\Date::excelToDateTimeObject($data['your_date_column'])->format('Y-m-d');
//...
}
/**
* List the validation rules
* @return array
*/
public function rules(): array
{
return [
'your_date_column'=>'required|date_format:Y-m-d',
//..
];
}
}
?>
That did the trick and the validation passes.
Solution 5:[5]
That "unknown number" is an excel timestamp, that way it stores the date and time data internally.
for example:
123213.0: it's just a date
213233.1233: is a date and time
0.1233: it's one hour
If you can map the cell and you know which column will always have a date / time / date-time you can use mapped cells or convert it manually, see: https://stackoverflow.com/a/59049044
Otherwise, if your need involves resolving datetime fields dynamically, I have written a method that is responsible for automatically detecting if the value is a datetime dynamically (regardless of whether or not you know if there will be a datetime in that column) or I have tried various data types and it works fine
/**
* @param Cell $cell
* @param $value
*
* @return boolean;
*/
public function bindValue(Cell $cell, $value)
{
$formatedCellValue = $this->formatDateTimeCell($value, $datetime_output_format = "d-m-Y H:i:s", $date_output_format = "d-m-Y", $time_output_format = "H:i:s" );
if($formatedCellValue != false){
$cell->setValueExplicit($formatedCellValue, DataType::TYPE_STRING);
return true;
}
// else return default behavior
return parent::bindValue($cell, $value);
}
/**
*
* Convert excel-timestamp to Php-timestamp and again to excel-timestamp to compare both compare
* By Leonardo J. Jauregui ( @Nanod10 | siskit dot com )
*
* @param $value (cell value)
* @param String $datetime_output_format
* @param String $date_output_format
* @param String $time_output_format
*
* @return $formatedCellValue
*/
private function formatDateTimeCell( $value, $datetime_output_format = "Y-m-d H:i:s", $date_output_format = "Y-m-d", $time_output_format = "H:i:s" )
{
// is only time flag
$is_only_time = false;
// Divide Excel-timestamp to know if is Only Date, Only Time or both of them
$excel_datetime_exploded = explode(".", $value);
// if has dot, maybe date has time or is only time
if(strstr($value,".")){
// Excel-timestamp to Php-DateTimeObject
$dateTimeObject = \PhpOffice\PhpSpreadsheet\Shared\Date::excelToDateTimeObject($value);
// if Excel-timestamp > 0 then has Date and Time
if(intval($excel_datetime_exploded[0]) > 0){
// Date and Time
$output_format = $datetime_output_format;
$is_only_time = false;
}else{
// Only time
$output_format = $time_output_format;
$is_only_time = true;
}
}else{
// Only Date
// Excel-timestamp to Php-DateTimeObject
$dateTimeObject = \PhpOffice\PhpSpreadsheet\Shared\Date::excelToDateTimeObject($value);
$output_format = $date_output_format;
$is_only_time = false;
}
// Php-DateTimeObject to Php-timestamp
$phpTimestamp = $dateTimeObject->getTimestamp();
// Php-timestamp to Excel-timestamp
$excelTimestamp = \PhpOffice\PhpSpreadsheet\Shared\Date::PHPToExcel( $phpTimestamp );
// if is only Time
if($is_only_time){
// 01-01-1970 = 25569
// Substract to match PhpToExcel conversion
$excelTimestamp = $excelTimestamp - 25569;
}
/*
// uncoment to debug manualy and see if working
$debug_arr = [
"value"=>$value,
"value_float"=>floatval($value),
"dateTimeObject"=>$dateTimeObject,
"phpTimestamp"=>$phpTimestamp,
"excelTimestamp"=>$excelTimestamp,
"default_date_format"=>$dateTimeObject->format('Y-m-d H:i:s'),
"custom_date_format"=>$dateTimeObject->format($output_format)
];
if($cell->getColumn()=="Q"){
if($cell->getRow()=="2"){
if(floatval($value)===$excelTimestamp){
dd($debug_arr);
}
}
}
*/
// if the values match
if( floatval($value) === $excelTimestamp ){
// is a fucking date! ;)
$formatedCellValue = $dateTimeObject->format($output_format);
return $formatedCellValue;
}else{
// return normal value
return false;
}
}
Solution 6:[6]
Simply use this function to store date.
use PhpOffice\PhpSpreadsheet\Shared;
public function collection(Collection $collection)
{
$errors = $this->validateBulk($collection);
if (!empty($errors)) {
return;
}
$holidays = [];
foreach ($collection as $col) {
Validator::make($col->toArray(), $this->rules())->validate();
$holidays[] = [
'title' => $col['title'],
'holiday_date' => Date::excelToDateTimeObject($col['holiday_date'])
->format('y-m-d'),
'holiday_year' => Date::excelToDateTimeObject($col['holiday_date'])
->format('y'),
];
$this->rows++;
}
Holidays::insert($holidays);
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Qraxin |
Solution 2 | D Malan |
Solution 3 | Nipun Tharuksha |
Solution 4 | Pathros |
Solution 5 | Leonardo Jauregui |
Solution 6 | Karl Hill |