'loop.nextitem doesn't work with current value from data
I need to compare postback.campaign_id
with the value of the next item. If it's similar, then, I don't print nothing, if not, then, print my row.
But, this code outputs everything.
<table>
<tr>
<td class="expand expand-campaign"><a>Test</a></td>
<td>{{ account_id }}</td>
</tr>
{% for postback in postbacks %}
{% if loop.nextitem is defined and postback.campaign_id != loop.nextitem[0] %}
<tr>
<td></td><td></td>
<td><input type="checkbox"></td>
<td class="expand expand-site"><a>{{ postback.campaign_id }}</a></td>
</tr>
{% endif %}
{% endfor %}
</table>
Solution 1:[1]
The loop.nextitem
contains the whole variable in your next item. So, if it is a dictionary or object, like in your case, you can access its properties like the current object under loop.
In your case that would mean:
postback.campaign_id != loop.nextitem.campaign_id
You also have the issue that your last item will always be skipped by the condition loop.nextitem is defined
. Since you are going to always print the last item of a streak of similar items, you can perfectly do:
{% if loop.nextitem is undefined
or postback.campaign_id != loop.nextitem.campaign_id
%}
Also note that, there is a loop.changed()
construct in Jinja that can be handy in this specific use case.
So, with a list like:
postbacks = [
{'campagn_id': 1},
{'campagn_id': 2},
{'campagn_id': 2},
{'campagn_id': 3},
{'campagn_id': 3},
]
And this snippet of Jinja:
<table>
{%- for postback in postbacks %}
{%- if loop.changed(postback.campaign_id) %}
<tr>
<td class="expand expand-site">
{{ postback.campaign_id }}
</td>
</tr>
{%- endif %}
{%- endfor %}
</table>
It renders, with some style added for clarity, as:
table {
border-collapse: collapse;
}
td {
border: 1px solid;
padding: 4px;
}
<table>
<tr>
<td class="expand expand-site">
1
</td>
</tr>
<tr>
<td class="expand expand-site">
2
</td>
</tr>
<tr>
<td class="expand expand-site">
3
</td>
</tr>
</table>
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | β.εηοιτ.βε |