'outlook vba code to display pictures in email

By default, my MS Outlook 2013 is set NOT to download images in received HTML e-mail messages. I would like to keep this setting.

There are some senders whose emails are handled by my Outlook VBA code...and filed into specific folders (rather than the INBOX). I do not use the in-built RULES.

These are known senders...and I would like to have the pictures in the emails from these SELECT KNOWN senders downloaded and displayed. I could do this manually for each email... by right clicking etc... but that is a pain... when there are many such emails.

I am unable to figure out the few lines of code (one line ?) required to download / enable display of images / pictures in the email. Something like... MailItem.Display (which does not work... it only displays the mail in an independent window)... or MailItem.DisplayImages (that is not a known method!).

I would include this one line (or lines) in the routine which handles emails from some known senders....so that their emails always have images / pictures downloaded and displayed.

Thanks.

vbaemailoutlook


Solution 1:[1]

You would need to set the PidTagBlockStatus property - see http://msdn.microsoft.com/en-us/library/ee219242(v=exchg.80).aspx.

Note that while you can read/write that property using MailItem.PropertyAccessor.SetProperty, you will not be able to calculate its value correctly - Outlook Object Model rounds off the value of the message delivery time, and you would need the raw Extended MAPI value (accessible in C++ or Delphi only) as the FileTime structure.

If using Redemption (I am its author) is an option, it exposes the RDOMail.DownloadPictures property. Something like the following should do the job (VB script):

  set Session = CreateObject("Redemption.RDOSession")
  Session.MAPIOBJECT = Application.Session.MAPIOBJECT
  set Item = Session.GetRDOObjectFromOutlookObject(YourOutlookItem)
  Item.DownloadPictures = true
  Item.Save

Solution 2:[2]

The Outlook object model doesn't provide any property or method for that.

Sources

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Source: Stack Overflow

Solution Source
Solution 1
Solution 2 Eugene Astafiev

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