'Pandas loop into variables adding suffix and transforming original column
I would like to loop into some variable name and the equivalent column with an added suffix "_plus"
#original dataset
raw_data = {'time': [2,1,4,2],
'zone': [5,1,3,0],
'time_plus': [5,6,2,3],
'zone_plus': [0,9,6,5]}
df = pd.DataFrame(raw_data, columns = ['time','zone','time_plus','zone_plus'])
df
#desired dataset
df['time']=df['time']*df['time_plus']
df['zone']=df['zone']*df['zone_plus']
df
I would like to do the multiplication in a more elegant way, through a loop, since I have many variables with this pattern: original name * transformed variable with the _plus suffix
something similar to this or better
my_list=['time','zone']
for i in my_list:
df[i]=df[i]*df[i+"_plus"]
Solution 1:[1]
Try:
for c in df.filter(regex=r".*(?<!_plus)$", axis=1):
df[c] *= df[c + "_plus"]
print(df)
Prints:
time zone time_plus zone_plus
0 10 0 5 0
1 6 9 6 9
2 8 18 2 6
3 6 0 3 5
Or:
for c in df.columns:
if not c.endswith("_plus"):
df[c] *= df[c + "_plus"]
Solution 2:[2]
raw_data = {'time': [2,1,4,2],
'zone': [5,1,3,0],
'time_plus': [5,6,2,3],
'zone_plus': [0,9,6,5]}
df = pd.DataFrame(raw_data, columns = ['time','zone','time_plus','zone_plus'])
# Take every column that doesn't have a "_plus" suffix
cols = [i for i in list(df.columns) if "_plus" not in i]
# Calculate new columns
for col in cols:
df[str(col+"_2")] = df[col]*df[str(col+"_plus")]
I decided to create the new columns with a "_2" suffix, this way we don't mess up the original data.
Solution 3:[3]
for c in df.columns:
if f"{c}_plus" in df.columns:
df[c] *= df[f"{c}_plus"]
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Andrej Kesely |
Solution 2 | leo_val |
Solution 3 | VaM |