'PHP Array split string and Integers

Below is an array of strings and numbers. How could the string and number values be split into separate arrays (with strings in one array and numbers in another array)?

array('a','b','c',1,2,3,4,5,'t','x','w')
phparrays


Solution 1:[1]

Loop through them, check if is_numeric and add to appropriate array:

$original = array('a','b','c',1,2,3,4,5,'t','x','w');

$letters = array();
$numbers = array();

foreach($original as $element){
    if(is_numeric($element)){
        $numbers[] = $element;
    }else{
        $letters[] = $element;
    }
}

https://3v4l.org/CAvVp

Solution 2:[2]

You could also do this in one line using array_filter()

$numbers = array_filter($arr,function($e){return is_numeric($e);});
$alphas = array_filter($arr,function($e){return !is_numeric($e);});

print_r($numbers);
print_r($alphas);

Solution 3:[3]

Using a foreach() like in @jnko's answer will be most performant because it only iterates over the array one time.

However, if you are not concerned with micro-optimization and prefer to write concise or functional-style code, then I recommend using array_filter() with is_numeric() calls, then making key comparisons between the first result and the original array.

Code: (Demo)

$array = ['a','b',0,'c',1,2,'ee',3,4,5,'t','x','w'];
$numbers = array_filter($array, 'is_numeric');
var_export($numbers);
var_export(array_diff_key($array, $numbers));

Output:

array (
  2 => 0,
  4 => 1,
  5 => 2,
  7 => 3,
  8 => 4,
  9 => 5,
)
array (
  0 => 'a',
  1 => 'b',
  3 => 'c',
  6 => 'ee',
  10 => 't',
  11 => 'x',
  12 => 'w',
)

Solution 4:[4]

    $data = array('a','b','c',1,2,3,4,5,'t','x','w');
    $integerArray = array();
    $stringArray = array();
    $undefinedArray = array();
    foreach($data as $temp)
    {
        if(gettype($temp) == "integer")
        {
            array_push($integerArray,$temp);
        }elseif(gettype($temp) == "string"){
            array_push($stringArray,$temp);
        }else{
            array_push($undefinedArray,$temp);
        }
    }

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 jnko
Solution 2 outlaw
Solution 3 mickmackusa
Solution 4 O?uzhan Filiz

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