'product variant price view table query
I have question need to query from product table and have many variants and prices, how can I show like below
product. variants. price
==========================
Coke -> Original -> 10$
-> Zero -> 8$
==========================
Pepsi -> Can -> 9$
-> Bottle. -> 10$
==========================
if I have 3 tables : products , variants , product_variant_tranx
any one can help me ?
Thanks
Solution 1:[1]
It's a little be late. But this type of question is common for newcomers. I put here my answer for the newcomers who are coming here to search exact type of problems solution.
Every product may generate a unique id like p1,p2,...
Under the products, you enter the variants like variant one, variant two,.. with a unique id(generate when entry, may be visible in the user interface or hidden for working backend) like p1v1,p1v2, with pricing like p1v1 10$,p1v2 8$ etc.
Let's see the tables
Table1. products_table
product_name | product_id |
---|---|
Coke | p1 |
Pepsi | p2 |
Table2. variants_table
product_id | variant_name | variant_id | variant_price |
---|---|---|---|
p1 | Original | p1v1 | 10$ |
p1 | Zero | p1v2 | 8$ |
p2 | Can | p2v1 | 9$ |
p2 | Bottle | p2v2 | 10$ |
Call to the user interface
Query1. SELECT product_name,product_id FROM products_table
Then call
Query2. SELECT variant_name,variant_id,variant_price FROM products_table WHERE product_id='getting product id from Query1'
I show the basic logic for newcomers. If having a large number of products and variants then inner looping can jam your server. For this, you may use the same database structures but can use advanced SQL queries.
Relative sources which may help:
https://dev.mysql.com/doc/ (For learning advanced SQL queries)
https://cashflowinventory.com/blog/cash-flow-inventory-tutorial-products-management/ (Get concepts from a likely application's product management interface)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Mohammad Ali |