'Retrieve array of substring matched with regex in swift
Is there any way to retrieve an array of words prefixed with @ sign in a string?
"@City == xyz AND @Hobby == gardening" -> ["@City","@Hobby"]
I tried below two methods but both are returning an empty array.
let regexp = "/@\\w*/g"
func matches(for regex: String, in text: String) -> [String] {
do {
let regex = try NSRegularExpression(pattern: regex)
let results = regex.matches(in: text,range: NSRange(text.startIndex..., in: text))
return results.map {
String(text[Range($0.range, in: text)!])
}
} catch let error {
print("invalid regex: \(error.localizedDescription)")
return []
}
}
extension String {
func regex (pattern: String) -> [String] {
do {
let regex = try NSRegularExpression(pattern: pattern, options: NSRegularExpression.Options(rawValue: 0))
let nsstr = self as NSString
let all = NSRange(location: 0, length: nsstr.length)
var matches : [String] = [String]()
regex.enumerateMatches(in: self, options: NSRegularExpression.MatchingOptions(rawValue: 0), range: all) {
(result : NSTextCheckingResult?, _, _) in
if let r = result {
let result = nsstr.substring(with: r.range) as String
matches.append(result)
}
}
return matches
} catch {
return [String]()
}
}
}
Solution 1:[1]
Your fundamental issue, as @jnpdx hinted at in a comment, is that your regexp
string contains control elements from another language. The following should solve your issue:
let regexp = "@\\w*"
You also get bogged down in unnecessary try-catch statements and outdated APIs based on Objective-C and their related type conversions. The following should do:
func matches(for regex: String, in text: String) -> [String] {
var result = [String]()
var startIndex = text.startIndex
let endIndex = text.endIndex
while let range = text.range(of: regex,
options: .regularExpression,
range: startIndex ..< endIndex)
{
result.append(String(text[range]))
startIndex = range.upperBound
}
return result
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | pommy |