'searching multiple Object Value in another Object JavaScript
I have 2 array of object in that, I want to compare all of the first array object property and value present in the second array of object. (at the object level.)
array 1
[
{
"id": "id1",
"name": "name1"
},
{
"id": "id3",
"name": "name3"
}
]
array 2
[
{
"id": "id1",
"name": "name1",
"other": "other"
},
{
"id": "id2",
"name": "name2",
"other": "other"
},
{
"id": "id3",
"name": "name3",
"other": "other"
}
]
In this case it will return true because, all of array 1 values present in array 2.
but if I have one property value that does not match with array 2, that will return false.
[
{
"id": "id1",
"name": "name1"
},
{
"id": "id5",
"name": "name3"
}
]
This will return false because { "id": "id5","name": "name3"} does not present in the array2.
I'm trying to compare with two for loop but I wanted to return false only once after both loop completes comparing all properties and value.now,
here is the two loops I'm trying, I know this is wrong because, it will return false when there is no value find and it will not go into the further loop.
for (var i = 0, i < a.length; i++) {
for (var j = 0, j < b.length; j++) {
if (b[j].id === a[i].id && b[j].name === a[i].name) {
console.log('all values found');
return true;
}
console.log('some values does not found');
return false;
}
}
I'm also using lodash.
Solution 1:[1]
Use lodash's _.intersectionBy()
, and compare the length of the result with the length of the shorter array:
var arr1 = [{"id":"id1","name":"name1","other":"other"},{"id":"id2","name":"name2","other":"other"},{"id":"id3","name":"name3","other":"other"}];
var arr2 = [{"id":"id1","name":"name1"},{"id":"id3","name":"name3"}];
var arr3 = [{"id":"id1","name":"name1"},{"id":"id5","name":"name3"}];
var result1_2 = _.intersectionBy(arr2, arr1, 'id').length === arr2.length;
var result1_3 = _.intersectionBy(arr3, arr1, 'id').length === arr3.length;
console.log(result1_2);
console.log(result1_3);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>
Solution 2:[2]
If the object properties have the same order, this could solve your problem:
const array1 = [
{
"id": "id1",
"name": "name1"
},
{
"id": "id2",
"name": "name2"
}
],
array2 = [
{
"id": "id1",
"name": "name1",
"other": "other"
},
{
"id": "id2",
"name": "name2",
"other": "other"
},
{
"id": "id3",
"name": "name3",
"other": "other"
}
];
let present = true,
item,
property,
properties;
for (let i = 0; i < array1.length && present; i++) {
item = array1[i];
properties = Object.keys(item);
for (let j = 0; j < properties.length; j++) {
property = item[properties[j]];
if (item.hasOwnProperty(properties[j])) {
if (property !== array2[i][Object.keys(array1[i])[j]]) {
present = false;
}
}
}
}
Solution 3:[3]
very simple an ugly way is to turn your objects into strings and compare them but this requires your object to have the same properties
var a1 = [
{
"id": "id1",
"name": "name1"
},
{
"id": "id3",
"name": "name3"
}
];
var a2 = [
{
"id": "id1",
"name": "name1",
},
{
"id": "id2",
"name": "name2",
},
{
"id": "id3",
"name": "name3",
}
];
var a3 = [
{
"id": "id1",
"name": "name1"
},
{
"id": "id5",
"name": "name3"
}
];
var doesArrayBContainArrayA = function(a,b)
{
var u = [];
a.map(e =>
{
var match = false;
b.forEach(function(bx){
if(!match){
match = JSON.stringify(bx) === JSON.stringify(e);
}
});
if (!match){
//console.log(JSON.stringify(bx)+'--'+JSON.stringify(e));
u.push(e); //add non existing item to temp array
}
});
return u.length === 0;
}
var result = doesArrayBContainArrayA(a3,a2);
var result2 = doesArrayBContainArrayA(a1,a2);
console.log(result);
console.log(result2);
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | w0l1w00d |
Solution 3 | Timtek |