'Using Selenium how to get network request

I want to take all the network request using selenium..I am not getting any way to find this solution.If anyone can suggest me or provide code or library that will be appreciated.

Network Request

javaselenium-webdriverwebdriver


Solution 1:[1]

Not exactly open by dev tools but found some network, performance and other results.

Yes you can do that using JavascriptExecutor

Below Code will give you all performance, network etc entries:-

ChromeOptions options = new ChromeOptions();
options.addArguments("start-maximized");
DesiredCapabilities capabilities = DesiredCapabilities.chrome();
capabilities.setCapability(ChromeOptions.CAPABILITY, options);
WebDriver driver = new ChromeDriver(capabilities);
driver.get("http://www.google.com");
String scriptToExecute = "var performance = window.performance || window.mozPerformance || window.msPerformance || window.webkitPerformance || {}; var network = performance.getEntries() || {}; return network;";
String netData = ((JavascriptExecutor)driver).executeScript(scriptToExecute).toString();
System.out.println(netData);

OR Below Code will give you specific performance entries:-

DesiredCapabilities d = DesiredCapabilities.chrome();
LoggingPreferences logPrefs = new LoggingPreferences();
logPrefs.enable(LogType.PERFORMANCE, Level.ALL);
d.setCapability(CapabilityType.LOGGING_PREFS, logPrefs);
WebDriver driver = new ChromeDriver(d);
driver.get("https://www.google.co.in/");
driver.manage().timeouts().implicitlyWait(15, TimeUnit.SECONDS);
LogEntries les = driver.manage().logs().get(LogType.PERFORMANCE);
for (LogEntry le : les) {
    System.out.println(le.getMessage());
}

The first code retrun network return network;" because of this JS tag. You can remove JS code of entity which you don't require

The second code return perfromance

Hope it will help you :)

Solution 2:[2]

It's working for me

ChromeOptions options = new ChromeOptions();
LoggingPreferences logPrefs = new LoggingPreferences();
logPrefs.enable( LogType.PERFORMANCE, Level.ALL );
options.setCapability( "goog:loggingPrefs", logPrefs );
WebDriverManager.chromedriver().setup();
WebDriver driver = new ChromeDriver(options);
driver.get("http://www.google.com");
    
List<LogEntry> entries = driver.manage().logs().get(LogType.PERFORMANCE).getAll();
System.out.println(entries.size() + " " + LogType.PERFORMANCE + " log entries found");
 for (LogEntry entry : entries) {
   System.out.println(entry.getMessage());
 }

Solution 3:[3]

  1. You can use "browsermob-proxy", "LoggingPreferences", "CloseableHttpClient", "HttpURLConnection" for getting the logs
  2. If you wish not to use browser and want to get the response, then I would suggest to go for "CloseableHttpClient".
  3. Copy the URI ("www.somewebsite.com/v1/api/sign-in?"). Get the request payload(which will be available in that particular API URI). Pass all the parameters with "&" like this "www.somewebsite.com/v1/api/sign-in?&username=xyz&password=1234566&app_id=12123214324234134&app_secret=213242345345345" (Remember app id and app secret is very unique and do not expose it anywhere)
  4. Once you get the URI, this code will give you JSON format response
            HttpPost request = new HttpPost(str);
            request.setHeader("content-type", "application/json");
            HttpResponse response = client.execute(request);
            BufferedReader bufReader = new BufferedReader(new InputStreamReader(
                    response.getEntity().getContent()));
            while ((line = bufReader.readLine()) != null) {
                builder=String.valueOf(line);
            }

            System.out.println(builder);
        }

Sources

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Source: Stack Overflow

Solution Source
Solution 1
Solution 2
Solution 3 StackExchange What The Heck

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