'ValueError: Incompatible indexer with Series while adding date to Date to Data Frame
I am new to python and I can't figure out why I get this error: ValueError: Incompatible indexer with Series.
I am trying to add a date to my data frame.
The date I am trying to add:
date = (chec[(chec['Día_Sem']=='Thursday') & (chec['ID']==2011957)]['Entrada'])
date
Date output:
56 1900-01-01 07:34:00
Name: Entrada, dtype: datetime64[ns]
Then I try to add 'date' to my data frame using loc:
rep.loc[2039838,'Thursday'] = date
rep
And I get this error:
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-347-3e0678b0fdbf> in <module>
----> 1 rep.loc[2039838,'Thursday'] = date
2 rep
~/anaconda3/lib/python3.7/site-packages/pandas/core/indexing.py in __setitem__(self, key, value)
188 key = com.apply_if_callable(key, self.obj)
189 indexer = self._get_setitem_indexer(key)
--> 190 self._setitem_with_indexer(indexer, value)
191
192 def _validate_key(self, key, axis):
~/anaconda3/lib/python3.7/site-packages/pandas/core/indexing.py in _setitem_with_indexer(self, indexer, value)
640 # setting for extensionarrays that store dicts. Need to decide
641 # if it's worth supporting that.
--> 642 value = self._align_series(indexer, Series(value))
643
644 elif isinstance(value, ABCDataFrame):
~/anaconda3/lib/python3.7/site-packages/pandas/core/indexing.py in _align_series(self, indexer, ser, multiindex_indexer)
781 return ser.reindex(ax)._values
782
--> 783 raise ValueError('Incompatible indexer with Series')
784
785 def _align_frame(self, indexer, df):
ValueError: Incompatible indexer with Series
Solution 1:[1]
Try date.iloc[0]
instead of date
:
rep.loc[2039838,'Thursday'] = date.iloc[0]
Because date
is actually a Series (so basically like a list/array) of the values, and .iloc[0]
actually selects the value.
Solution 2:[2]
You use loc to get a specific value, and your date type is a series or dataframe, the type between the two can not match, you can change the code to give the value of date to rep.loc[2039838,'Thursday'], for example, if your date type is a series and is not null, you can do this:
rep.loc[2039838,'Thursday'] = date.values[0]
Solution 3:[3]
I was also facing similar issue but in a different scenario. I came across threads of duplicate indices, but of-course that was not the case with me. What worked for me was to use .at
in place of .loc
. So you can try and see if it works
rep['Thursday'].at[2039838] = date.values[0]
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | richardec |
Solution 2 | maya |
Solution 3 | Vinod Kumar |