I'm coding a website in Arabic language content. Problem: the down arrow of an accordion button should be in the far left. This is my code: <link href
I want to reverse the output of the code. goal(hall). move(gateA,gateB). move(gateA,gateG). move(gateB,gateC). move(gateB,gateH). move(gateG,gateL). move(gateG,
I tried coderbyte and looks something is wrong with it. The first challenge is simply to reverse a string. I did this in java: import java.util.*; import java
I often use .slice().reverse() in *ngFor to display elements in reverse order. But now I have a problem, because I also use | keyvalue. How to use .slice().reve
In this program, the user is allowed to enter words of up to 20 letters, which are stored in another array and printed from the end. But there is error on my co
How do I reverse each uppercase and lowercase ("I am A Great human") to ("I ma A Taerg namuh")? This is the code I Have: function wordsReverse(str) { let wo
Am trying to reverse a string using a method in java, I can fetch all the elements of the string and print them out in order via a loop, my problem is reversing
Recently and overnight, Apache's error logs from a couple of nodejs servers have been filling with this: [proxy:error] [pid xxx] (32)Broken pipe: [client xxx.x
user=> (rseq [:a :b]) (:b :a) user=> (rseq (rseq [:a :b])) ClassCastException clojure.lang.APersistentVector$RSeq cannot be cast to clojure.lang.Reversi
This is an homework problem Is there a way tor reverse a number in Java without using any loops? The only solution I can think of is reversing it using String
So I want a LinearProgressBar that goes from right to left. So basically in reverse. Is there a line of code I need to add? Couldn't find anyt
The first thing that comes to mind is: >>> l = list('abcdef') >>> for i in range(len(l)-1, -1, -1): ... item = l[i] ... print(i, item) ...
I am attempting to reverse an array using a stack. However, I get an error on arr[i] = stack.top();, and the suggestion to resolve it in Eclipse is to change it
For example: My string is: 123456789 nn nn oo nn nn mlm nn203. My target is: nn. Then, I match string from the end to the beginning and return the first ma