'Check for multi-line content in a file
I'm trying to check if a multi-line string exists in a file using common bash commands (grep, awk, ...).
I want to have a file with a few lines, plain lines, not patterns, that should exists in another file and create a command (sequence) that checks if it does. If grep could accept arbitrary multiline patterns, I'd do it with something similar to
grep "`cat contentfile`" targetfile
As with grep I'd like to be able to check the exit code from the command. I'm not really interested in the output. Actually no output would be preferred since then I don't have to pipe to /dev/null.
I've searched for hints, but can't come up with a search that gives any good hits. There's How can I search for a multiline pattern in a file?, but that is about pattern matching.
I've found pcre2grep, but need to use "standard" *nix tools.
Example:
contentfile:
line 3
line 4
line 5
targetfile:
line 1
line 2
line 3
line 4
line 5
line 6
This should match and return 0 since the sequence of lines in the content file is found (in the exact same order) in the target file.
EDIT: Sorry for not being clear about the "pattern" vs. "string" comparison and the "output" vs. "exit code" in the previous versions of this question.
Solution 1:[1]
Following up on a comment from Cyrus, who pointed to How to know if a text file is a subset of another, the following Python one-liner does the trick
python -c "content=open('content').read(); target=open('target').read(); exit(0 if content in target else 1);"
Solution 2:[2]
You didn't say if you wanted a regexp match or string match and we can't tell since you named your search file "patternfile" and a "pattern" could mean anything and at one point you imply you want to do a string match (check if a multi-line _string_ exists) but then you're using grep and pcregpre with no stated args for string rather than regexp matches.
In any case, these will do whatever it is you want using any awk (which includes POSIX standard awk and you said you wanted to use standard UNIX tools) in any shell on every UNIX box:
For a regexp match:
$ cat tst.awk
NR==FNR { pat = pat $0 ORS; next }
{ tgt = tgt $0 ORS }
END {
while ( match(tgt,pat) ) {
printf "%s", substr(tgt,RSTART,RLENGTH)
tgt = substr(tgt,RSTART+RLENGTH)
}
}
$ awk -f tst.awk patternfile targetfile
line 3
line 4
line 5
For a string match:
$ cat tst.awk
NR==FNR { pat = pat $0 ORS; next }
{ tgt = tgt $0 ORS }
END {
lgth = length(pat)
while ( beg = index(tgt,pat) ) {
printf "%s", substr(tgt,beg,lgth)
tgt = substr(tgt,beg+lgth)
}
}
$ awk -f tst.awk patternfile targetfile
line 3
line 4
line 5
Having said that, with GNU awk you could do the following if you're OK with a regexp match and backslash interpretation of the patternfile contents (so \t is treated as a literal tab):
$ awk -v RS="$(cat patternfile)" 'RT!=""{print RT}' targetfile
line 3
line 4
line 5
or with GNU grep:
$ grep -zo "$(cat patternfile)" targetfile | tr '\0' '\n'
line 3
line 4
line 5
There are many other options depending on what kind of match you're really trying to do and which tools versions you have available.
Solution 3:[3]
EDIT: Since OP needs outcome of command in form of true or false(yes or no), so edited command in that manner now(created and tested in GNU awk).
awk -v message="yes" 'FNR==NR{a[$0];next} ($0 in a){if((FNR-1)==prev){b[++k]=$0} else {delete b;k=""}} {prev=FNR}; END{if(length(b)>0){print message}}' patternfile targetfile
Could you please try following, tested with given samples and it should print all continuous lines from pattern file if they are coming in same order in target file(count should be at least 2 for continuous lines in this code).
awk '
FNR==NR{
a[$0]
next
}
($0 in a){
if((FNR-1)==prev){
b[++k]=$0
}
else{
delete b
k=""
}
}
{
prev=FNR
}
END{
for(j=1;j<=k;j++){
print b[j]
}
}' patternfile targetfile
Explanation: Adding explanation for above code here.
awk ' ##Starting awk program here.
FNR==NR{ ##FNR==NR will be TRUE when first Input_file is being read.
a[$0] ##Creating an array a with index $0.
next ##next will skip all further statements from here.
}
($0 in a){ ##Statements from here will will be executed when 2nd Input_file is being read, checking if current line is present in array a.
if((FNR-1)==prev){ ##Checking condition if prev variable is equal to FNR-1 value then do following.
b[++k]=$0 ##Creating an array named b whose index is variable k whose value is increment by 1 each time it comes here.
}
else{ ##Mentioning else condition here.
delete b ##Deleting array b here.
k="" ##Nullifying k here.
}
}
{
prev=FNR ##Setting prev value as FNR value here.
}
END{ ##Starting END section of this awk program here.
for(j=1;j<=k;j++){ ##Starting a for loop here.
print b[j] ##Printing value of array b whose index is variable j here.
}
}' patternfile targetfile ##mentioning Input_file names here.
Solution 4:[4]
another solution in awk:
echo $(awk 'FNR==NR{ a[$0]; next}{ x=($0 in a)?x+1:0 }x==length(a){ print "OK" }' patternfile targetfile )
This returns "OK" if there is a match.
Solution 5:[5]
a one-liner:
$ if [ $(diff --left-column -y patternfile targetfile | grep '(' -A1 -B1 | tail -n +2 | head -n -1 | wc -l) == $(cat patternfile | wc -l) ]; then echo "ok"; else echo "error"; fi
explanation:
first is to compare the two files using diff:
diff --left-column -y patternfile targetfile
> line 1
> line 2
line 3 (
line 4 (
line 5 (
> line 6
then filter to show only interesting lines, which are the lines the '(', plus extra 1-line before, and after match, to check if lines in patternfile match without a break.
diff --left-column -y patternfile targetfile | grep '(' -A1 -B1
> line 2
line 3 (
line 4 (
line 5 (
> line 6
Then leave out the first, and last line:
diff --left-column -y patternfile targetfile | grep '(' -A1 -B1 | tail -n +2 | head -n -1
line 3 (
line 4 (
line 5 (
add some code to check if the number of lines match the number of lines in the patternfile:
if [ $(diff --left-column -y patternfile targetfile | grep '(' -A1 -B1 | tail -n +2 | head -n -1 | grep '(' | wc -l) == $(cat patternfile | wc -l) ]; then echo "ok"; else echo "error"; fi
ok
to use this with a return-code, a script could be created like this:
#!/bin/bash
patternfile=$1
targetfile=$2
if [ $(diff --left-column -y $patternfile $targetfile | grep '(' -A1 -B1 | tail -n +2 | head -n -1 | grep '(' | wc -l) == $(cat $patternfile | wc -l) ];
then
exit 0;
else
exit 1;
fi
The test (when above script is named comparepatterns):
$ comparepatterns patternfile targgetfile
echo $?
0
Solution 6:[6]
The easiest way to do this is to use a sliding window. First you read the pattern file, followed by file to search.
(FNR==NR) { a[FNR]=$0; n=FNR; next }
{ b[FNR]=$0 }
(FNR >= n) { for(i=1; i<=n;++i) if (a[i] != b[FNR-n+i]) { delete b[FNR-n+1]; next}}
{ print "match at", FNR-n+1}
{ r=1}
END{ exit !r}
which you call as
awk -f script.awk patternFile searchFile
Solution 7:[7]
Unless you're talking about 10 GB+, here's an awk-based solution that's fast and clean :
mawk '{ exit NF==NR }' RS='^$' FS="${multiline_pattern}"
- The pattern exists only in the file
"${m2p}" - which is embedded within multi-file pipeline of 1st test,
- but not 2nd one
This solution, for now, doesn't auto handle instances where regex meta-character escaping is needed. Alter it as you see fit.
Unless the pattern occurs far too often, it might even save time to do it all at once instead of having to check line-by-line, including saving lines along the way in some temp pattern space.
NR is always 1 there since RS is forced to the tail end of the input. NF is larger than 1 only when the pattern is found. By evaluating exit NF == NR, it inverts the match, thus matching structure of posix exit codes.
% echo; ( time ( \
\
echo "\n\n multi-line-pattern :: \n\n " \
"-------------\n${multiline_pattern}\n" \
" -----------\n\n " \
"$( nice gcat "${m2m}" "${m3m}" "${m3l}" "${m2p}" \
"${m3r}" "${m3supp}" "${m3t}" | pvE0 \
\
| mawk2 '{ exit NF == NR
}' RS = '^$' \
FS = "${multiline_pattern}" \
\
) exit code : ${?} " ) ) | ecp
in0: 3.10GiB 0:00:01 [2.89GiB/s] [2.89GiB/s] [ <=> ]
( echo ; ) 0.77s user 1.74s system 110% cpu 2.281 total
multi-line-pattern ::
-------------
77138=1159=M
77138=1196=M
77138=1251=M
77138=1252=M
77138=4951=M
77138=16740=M
77138=71501=M
-----------
exit code : 0
% echo; ( time ( \
\
echo "\n\n multi-line-pattern :: \n\n " \
"-------------\n${multiline_pattern}\n" \
" -----------\n\n " \
"$( nice gcat "${m2m}" "${m3m}" "${m3l}" \
"${m3r}" "${m3supp}" "${m3t}" | pvE0 \
\
| mawk2 '{ exit NF == NR
}' RS = '^$' \
FS = "${multiline_pattern}" \
\
) exit code : ${?} " ) ) | ecp
in0: 2.95GiB 0:00:01 [2.92GiB/s] [2.92GiB/s] [ <=> ]
( echo ; ) 0.64s user 1.65s system 110% cpu 2.074 total
multi-line-pattern ::
-------------
77138=1159=M
77138=1196=M
77138=1251=M
77138=1252=M
77138=4951=M
77138=16740=M
77138=71501=M
-----------
exit code : 1
If your pattern is the full file, then something like this - even when using the full file as a single gigantic 153 MB pattern, it finished in less than 2.4 secs against ~3 GB input.
echo
( time ( nice gcat "${m2m}" "${m3m}" "${m3l}" "${m3r}" "${m3supp}" "${m3t}" | pvE0 \
\
| mawk2 -v pattern_file="${m2p}" '
BEGIN {
RS = "^$"
getline FS < pattern_file
close(pattern_file)
} END {
exit NF == NR }' ; echo "\n\n exit code :: $?\n\n" ))|ecp;
du -csh "${m2p}" ;
( time ( nice gcat "${m2m}" "${m3m}" "${m3l}" \
"${m2p}" "${m3r}" "${m3supp}" "${m3t}" | pvE0 \
\
| mawk2 -v pattern_file="${m2p}" '
BEGIN {
RS = "^$"
getline FS < pattern_file
close(pattern_file)
} END {
exit NF == NR }' ; echo "\n\n exit code :: $?\n\n" ))|ecp;
in0: 2.95GiB 0:00:01 [2.58GiB/s] [2.58GiB/s] [ <=> ]
( nice gcat "${m2m}" "${m3m}" "${m3l}" "${m3r}" "${m3supp}" "${m3t}" | pvE 0.)
0.82s user 1.71s system 111% cpu 2.260 total
exit code :: 1
153M /Users/************/m2map_main.txt
153M total
in0: 3.10GiB 0:00:01 [2.56GiB/s] [2.56GiB/s] [ <=> ]
( nice gcat "${m2m}" "${m3m}" "${m3l}" "${m2p}" "${m3r}" "${m3supp}" "${m3t}")
0.83s user 1.79s system 112% cpu 2.339 total
exit code :: 0
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | thoni56 |
| Solution 2 | |
| Solution 3 | |
| Solution 4 | Luuk |
| Solution 5 | |
| Solution 6 | |
| Solution 7 |