'How do I idiomatically convert a bool to an Option or Result in Rust?
It seems there is no way of such one-line conversion using std
.
I do not like this kind of verbosity:
match my_bool {
true => Ok(()),
false => Err(MyError::False),
}
I would like to use a one-liner, for example:
let my_bool = true;
let my_option = my_bool.to_option(MyObject{}); // true => MyObject{}, false => None
let my_result = my_bool.to_result(MyObject{}, MyError{}); // true => MyObject{}, false => MyError{}
What is the shortest piece of code for doing that?
Solution 1:[1]
This answer is somewhat outdated. Starting with Rust 1.50, you can use the built-in bool::then
. See the other answers above for more information.
There is the boolinator
crate. It defines the extension trait Boolinator
for bool
which adds a couple of useful methods. Example:
use boolinator::Boolinator;
my_bool.as_some(MyObject {}); // Option<MyObject>
my_bool.as_result(MyObject {}, MyError {}); // Result<MyObject, MyError>
A true
value leads to Some(_)
or Ok(_)
, while a false
value leads to None
or Err(_)
.
There is an issue about adding functionality like this to std
on the RFCs repository, but it doesn't look like it's happening anytime soon.
Solution 2:[2]
As of Rust 1.50 you can use bool::then
:
assert_eq!(false.then(|| val), None);
assert_eq!(true.then(|| val), Some(val));
You can convert it to a Result
by chaining Option::ok_or
:
assert_eq!(false.then(|| val).ok_or(err), Err(err));
assert_eq!(true.then(|| val).ok_or(err), Ok(val));
On nightly, you can use bool::then_some
and pass a value directly instead of creating a closure:
#![feature(bool_to_option)]
assert_eq!(false.then_some(val), None);
assert_eq!(true.then_some(val), Some(val));
Alternatively, you can use Option::filter
:
assert_eq!(Some(obj).filter(|_| false), None);
assert_eq!(Some(obj).filter(|_| true).ok_or(err), Ok(obj));
Solution 3:[3]
bool.then_some()
does this:
let my_bool = true;
let my_option = my_bool.then_some(MyObject{});
let my_result = my_bool.then_some(MyObject{}).ok_or(MyError{});
At the time of writing, this is still part of the experimental bool_to_option
feature.
Solution 4:[4]
Use an if
expression:
if my_bool { Ok(()) } else { Err(MyError::False) }
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Ibraheem Ahmed |
Solution 2 | OliveIsAWord |
Solution 3 | user4815162342 |
Solution 4 | Shepmaster |