'How do I idiomatically convert a bool to an Option or Result in Rust?

It seems there is no way of such one-line conversion using std.

I do not like this kind of verbosity:

match my_bool {
    true => Ok(()),
    false => Err(MyError::False),
}

I would like to use a one-liner, for example:

let my_bool = true;
let my_option = my_bool.to_option(MyObject{}); // true => MyObject{}, false => None
let my_result = my_bool.to_result(MyObject{}, MyError{}); // true => MyObject{}, false => MyError{}

What is the shortest piece of code for doing that?



Solution 1:[1]

This answer is somewhat outdated. Starting with Rust 1.50, you can use the built-in bool::then. See the other answers above for more information.


There is the boolinator crate. It defines the extension trait Boolinator for bool which adds a couple of useful methods. Example:

use boolinator::Boolinator;

my_bool.as_some(MyObject {});                // Option<MyObject>
my_bool.as_result(MyObject {}, MyError {});  // Result<MyObject, MyError>

A true value leads to Some(_) or Ok(_), while a false value leads to None or Err(_).

There is an issue about adding functionality like this to std on the RFCs repository, but it doesn't look like it's happening anytime soon.

Solution 2:[2]

As of Rust 1.50 you can use bool::then:

assert_eq!(false.then(|| val), None);
assert_eq!(true.then(|| val), Some(val));

You can convert it to a Result by chaining Option::ok_or:

assert_eq!(false.then(|| val).ok_or(err), Err(err));
assert_eq!(true.then(|| val).ok_or(err), Ok(val));

On nightly, you can use bool::then_some and pass a value directly instead of creating a closure:

#![feature(bool_to_option)]

assert_eq!(false.then_some(val), None);
assert_eq!(true.then_some(val), Some(val));

Alternatively, you can use Option::filter:

assert_eq!(Some(obj).filter(|_| false), None);
assert_eq!(Some(obj).filter(|_| true).ok_or(err), Ok(obj));

Solution 3:[3]

bool.then_some() does this:

let my_bool = true;
let my_option = my_bool.then_some(MyObject{});
let my_result = my_bool.then_some(MyObject{}).ok_or(MyError{});

At the time of writing, this is still part of the experimental bool_to_option feature.

Solution 4:[4]

Use an if expression:

if my_bool { Ok(()) } else { Err(MyError::False) }

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Ibraheem Ahmed
Solution 2 OliveIsAWord
Solution 3 user4815162342
Solution 4 Shepmaster