'How to add red asterisk in label of TextFormField In Flutter
Solution 1:[1]
Simplest way, but not exactly equals:
TextField(
decoration: InputDecoration(
hintText: 'Ciao',
suffixText: '*',
suffixStyle: TextStyle(
color: Colors.red,
),
),
),
Or create a custom TextField
to use hint as Widget instead of String
You can use my two customized files:
TextFieldCustom(
hintText: Text.rich(
TextSpan(
text: 'FIRST NAME',
children: <InlineSpan>[
TextSpan(
text: '*',
style: TextStyle(color: Colors.red),
),
],
style: TextStyle(color: Colors.black54),
),
),
),
Solution 2:[2]
Try these two files I had same requirement.
Just add attribute isMandate: true
in CInputDecoration and use CTextField.
CTextField(
...
decoration: new CInputDecoration(
isMandate: true,
...
))
https://github.com/sumit1954/Flutter/blob/master/CInputDecorator.dart https://github.com/sumit1954/Flutter/blob/master/CTextField.dart
Solution 3:[3]
Achieved this in hard fast way. Replace input_decorator.dart with below code:
https://github.com/neal786y/InputDecoratorForMandatoryFields/blob/master/input_decorator.dart
In your InputDecoration scope add a property "isMandatoryField: true"
Worked for me on temporary basis.
Solution 4:[4]
With the latest version of flutter you can also send a widget in label parameter. So, something like this is possible
label: Row(
mainAxisSize: MainAxisSize.min,
children: [
Text(label.replaceAll('*', '')),
label.contains('*')
? Text(
'*',
style: TextStyle(color: Colors.red),
)
: Container(),
],
),
Solution 5:[5]
Place this code in TextFormField or TextField
this label works as an hint property
label: RichText(
text: TextSpan(
text: 'Full Name',
style: const TextStyle(
color: Colors.grey),
children: [
TextSpan(
text: ' *',
style: TextStyle(
color: Colors.red,
)
)
]
),
floatingLabelBehavior:FloatingLabelBehavior.never,
look at above screenshot of label parameter holding a Widget
not a String
without any error
Solution 6:[6]
Use label
property inside InputDecorator
See this answer https://stackoverflow.com/a/72209425/8913302
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | andrea689 |
Solution 2 | Sumit |
Solution 3 | user8253154 |
Solution 4 | Cedric Wilson |
Solution 5 | |
Solution 6 | Johan |