'How to open url with selenium webdriver python with differents IPs?
from selenium import webdriver
options = webdriver.ChromeOptions()
options.add_argument('--proxy-server=125.62.213.229:82')
browser = webdriver.Chrome(executable_path='F:\Drivers\ChromeDriver\chromedriver.exe', chrome_options=options)
browser.get("http://www.whatismyipaddress.com")
I dont know to apply loop in this.
Solution 1:[1]
using .format to substitute.
ip=['125.62.213.229:82'] # add others here.
for i in ip:
options.add_argument(('--proxy-server={0}').format(i))
#rest of your code
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Linda |