'Linux - How to get a string specific string from a specific line?

Lets say that I have the following DeletedFiles.txt file:

test1.zip  -  date-removed='6-16-2021'
test2.zip  -  date-removed='6-17-2021'
test3.zip  -  date-removed='6-17-2021'
test4.zip  -  date-removed='6-17-2021'

I want to for example only grab the date from test3.zip.

I have the number of the line that test3.zip is on.

How can I make it so that when I run the following code it only returns the date from the specific file I want it from, in this case from the file test3.zip so that the output will be 6-17-2021

I have the following code:

Line=$(GetLine $File)
LineNumber=`echo $Line | cut -c1-1`
DateRemoved=$(sed -e "s/.*'\(.*\)'/\1/" DeletedFiles.txt)
echo "$DateRemoved"

But when I run this it returns the dates from ALL the files:

6-16-2021
6-17-2021
6-17-2021
6-17-2021

And when I try the following code:

Line=$(GetLine $File)
LineNumber=`echo $Line | cut -c1-1`
DateRemoved=$(sed -e "/$LineNumber/s/.*'\(.*\)'/\1/" DeletedFiles.txt)
echo "$DateRemoved"

It returns everything from ALL lines:

test1.zip  -  date-removed='6-16-2021'
test2.zip  -  date-removed='6-17-2021'
test3.zip  -  date-removed='6-17-2021'
test4.zip  -  date-removed='6-17-2021'

How can I fix this so that it only returns the date from the file I want?

linuxbashshell


Solution 1:[1]

With a simple command you can solve it. grep test3\.zip DeletedFiles.txt

Solution 2:[2]

I'd use awk for this:

$ awk -F"[ ']" -v file="test3.zip" '$1 == file {print $(NF-1)}' DeletedFiles.txt
6-17-2021

Solution 3:[3]

With sed

sed -n "/^test3\.zip /s/.*date-removed='\([^']*\).*/\1/p" file.txt

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1
Solution 2 glenn jackman
Solution 3 Jetchisel

Related Questions