'Microsoft Graph Api User.Read.All Not granted for my domain
I am getting the following error or status Not granted for my domain
. see the attached document
Is this because my role is User
?
I tried to find who is Azure AD Global Administrator
?
I followed the following steps:
- Log into the Azure Portal
(https://portal.azure.com)
. - Click on
Azure Active Directory
- Click on
Roles and administrators
- Click on
Global administrator
- Under
Global administrator
it saysMicrosoft Office 365 Portal
what does it mean?
How can I or someone else in organization become Global administrator
?
I want API permissions->User.Read.All
Not granted for mydomain
PS: My email is work email
.
Update 2Global administrator - Assignments
say's Microsoft Office 365 Portal
is my Admin. How to get these credentials?
Solution 1:[1]
I was similiarly frustrated here: it's very hard to spot, however you'll notice that the 'grant admin consent for -' is reset on every update to permissions.
Therefore: simply re-tick this and wait a few seconds for the warnings to disappear.
I too thought I was missing a step elsewhere, very misleading!
Solution 2:[2]
For User.Read.All
permission you should have Admin Consent
which a User
cannot avail.
You should have either Global Admin
or Application administrator
credentials.
Permission Required:
Please refer to this official document Permission details
Admin Credentials:
For Admin credentials details refer to this document
Office 365 Admin Role Assignment:
Hope this will help. Let me know if you have any more concern.
Solution 3:[3]
Make sure that if you're the only one or just opened the account that you are an admin on Microsoft 365.
- You will need to add a TXT record in your DNS settings (F.e. Route53 - AWS) https://docs.microsoft.com/en-us/microsoft-365/admin/misc/become-the-admin?view=o365-worldwide
Once that is verified you will automatically be a global administrator and then you will have access to all admin features.
- Go back to Azure and then just click on the small hard to see in grey here:
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
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Solution 3 | Tra |