'MongoDB Group by field, count it with condition
I would like to count different hu for a shipment. So I write this query but how I can count different hu group by shipment ?
my query :
db.eventstranslated.aggregate([
{ "$group": {
"_id": "$IdShipment",
"count": { "$sum": 1 }
}},
{ "$group": {
"_id": null,
"ship": {
"$push": {
"shipment": "$_id",
"count": "$count"
}
}
}},
{ "$project": { "_id": 0 }}
])
Result :
{ shipment: A01, count: 1 },
{ shipment: A02, count: 1 },
expect output:
{shipment: A01, count: 2 }
{shipment: A02, count: 1 }
my collection:
{
_id: 1,
IdShipment: "A01",
hu: "C111"
},
{
_id: 2,
IdShipment: "A01",
hu: "C112"
},
{
_id: 3,
IdShipment: "A02",
hu: "D111"
},
{
_id: 4,
IdShipment: "A02",
hu: "D111"
}
Solution 1:[1]
You can use two $group
stages like this:
First $group
has a compound key to get all differents options, and the second $group
is to get only differents IdShipment
.
db.collection.aggregate([
{
"$group": {
"_id": {
"IdShipment": "$IdShipment",
"hu": "$hu"
}
}
},
{
"$group": {
"_id": "$_id.IdShipment",
"count": {
"$sum": 1
}
}
}
])
Example here
Also you can use $project
to output the name you want. Example here
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | J.F. |