'Script linux loop for multiple number
I have a list of Linux commands that I need to repeat up to 670. How can I automate the commands, so I don't have to do the 670 times. I don't know how to do all the operations from C1, C2, C3 .... to C670?
#START C1
mkdir C1
cd C1
awk '/Prymnesium_parvum_GenomeV1.0_Contig_1\t/' ../Methy_670.txt | cut -f 2 > IllU_C1.txt
awk '/Prymnesium_parvum_GenomeV1.0_Contig_1\t/' ../TE/TEannotation_Prymnesium_parvum_GenomeV1.0.gff3 | cut -f 4,5 > TE_C1.txt
paste TE_C1.txt IllU_C1.txt> C1.txt
awk -f ../com.awk C1.txt C1.txt > res_C1
wc -l res_C1
wc -l TE_C1.txt
cd ..
###Stop C1
#Start C2
mkdir C2
cd C2
awk '/Prymnesium_parvum_GenomeV1.0_Contig_2\t/' ../Methy_670.txt | cut -f 2 > IllU_C1.txt
awk '/Prymnesium_parvum_GenomeV1.0_Contig_2\t/' ../TE/TEannotation_Prymnesium_parvum_GenomeV1.0.gff3 | cut -f 4,5 > TE_C1.txt
....
Solution 1:[1]
Not tested:
#!/bin/bash
for C in {1..670};do
echo START ${C}
mkdir -p ${C} && cd ${C}
awk '/Prymnesium_parvum_GenomeV1.0_Contig_'${C}'\t/' ../Methy_670.txt | cut -f 2 > IllU_${C}.txt
awk '/Prymnesium_parvum_GenomeV1.0_Contig_'${C}'\t/' ../TE/TEannotation_Prymnesium_parvum_GenomeV1.0.gff3 | cut -f 4,5 > TE_${C}.txt
paste TE_${C}.txt IllU_${C}.txt> ${C}.txt
awk -f ../com.awk ${C}.txt ${C}.txt > res_${C}
wc -l res_${C}
wc -l TE_${C}.txt
cd ..
echo Stop ${C}
done
I am not sure what awk '/Prymnesium_parvum_GenomeV1.0_Contig_1\t/' ../Methy_670.txt
does but you will have to figure out how you can add ${C} in there as single quotes will not parse ${C}
Solution 2:[2]
Another take: awk can do what cut does
#!/usr/bin/env bash
prep_dir() {
local n=$1
local c=C$n ill=IllU_$c.txt te=TE_$c.txt
local pattern="Prymnesium_parvum_GenomeV1.0_Contig_${n}\t"
if mkdir "$c" && cd "$c"; then
awk -v p="$pattern" '$0 ~ p {print $2}' ../Methy_670.txt > "$ill"
awk -v p="$pattern" '$0 ~ p {print $4, $5}' ../TE/TEannotation_Prymnesium_parvum_GenomeV1.0.gff3 > "$te"
paste "$te" "$ill" > "$c.txt"
awk -f ../com.awk "$c.txt" "$c.txt" > "res_$c"
wc -l "res_$c"
wc -l "$te"
cd ..
fi
}
for i in {1..670}; do
prep_dir $i
done
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | |
Solution 2 | glenn jackman |