'SQL group by in Subquery
I'm trying to get monthly production using group by after converting the unix column into regular timestamp. Can you please tell how to use group by here in the code.
'''
With production(SystemId, dayof, monthof, yearof, powerwatts, productionwattshours) as
(
Select SystemId,
[dayof] = DAY(hrdtc),
[monthof] = MONTH(hrdtc),
[yearof] = YEAR(hrdtc),
powerwatts, productionwatthours
from (
Select * , dateadd(s, UnixTime, '19700101') as hrdtc from meterreading ) ds
)
Select * from production
where systemId = 2368252
'''
Solution 1:[1]
I think you're looking for this (technically you don't need a subquery but it allows you to avoid repeating the DATEADD()
expression):
SELECT SystemId = 2368252,
[Month] = DATEFROMPARTS(YEAR(hrdtc), MONTH(hrdtc), 1),
powerwatts = SUM(powerwatts),
productionwatthours = SUM(productionwatthours)
FROM
(
SELECT powerwatts, productionwatthours,
DATEADD(SECOND, UnixTime, '19700101') as hrdtc
FROM dbo.enphasemeterreading
WHERE systemId = 2368252
) AS ds
GROUP BY DATEFROMPARTS(YEAR(hrdtc), MONTH(hrdtc), 1);
If you want to also avoid repeating the GROUP BY
expression:
SELECT SystemId = 2368252,
[Month],
powerwatts = SUM(powerwatts),
productionwatthours = SUM(productionwatthours)
FROM
(
SELECT [Month] = DATEFROMPARTS(YEAR(hrdtc), MONTH(hrdtc), 1),
powerwatts, productionwatthours
FROM
(
SELECT powerwatts, productionwatthours,
DATEADD(SECOND, UnixTime, '19700101') as hrdtc
FROM dbo.enphasemeterreading
WHERE systemId = 2368252
) AS ds1
) AS ds2
GROUP BY [Month];
Personally I don't think that's any prettier or clearer. A couple of other tips:
- Spell it out; shorthand is lazy and problematic
- Always qualify tables and other objects with schema
Updated requirement (please state these up front): How would I join this query to another table?
SELECT * FROM dbo.SomeOtherTable AS sot
INNER JOIN
(
SELECT SystemId = 2368252,
[Month],
powerwatts = SUM(powerwatts),
productionwatthours = SUM(productionwatthours)
FROM
...
GROUP BY [Month]
) AS agg
ON sot.SystemId = agg.SystemId;
Sources
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Source: Stack Overflow
Solution | Source |
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Solution 1 |