'Bitly API v4 - VBA Excel Macro

I'm trying to get the shorten bit.y URL in my excel file, but instead I'm obtainig the following message,

{"created_at":"2022-05-04T21:48:32+0000","id":"bitly.is/3w7FK4r","link":"https://bitly.is/3w7FK4r","custom_bitlinks":[],"long_url":"https://dev.bitly.com/","archived":false,"tags":[],"deeplinks":[],"references":{"group":"https://api-ssl.bitly.com/v4/groups/Bj7c1Yrhshv"}

how can i extract from that response only the part "link":"https://bitly.is/3w7FK4r

Option Explicit

Private Sub Worksheet_Change(ByVal Target As Range)

If Not Intersect(Target, Me.Range("B6:B100")) Is Nothing Then
    If Target.Count > 1 Then Exit Sub 'If users selects more than one cell, exit sub to prevent bugs
    If Target.Value = vbNullString Then Exit Sub
    
    Dim AccToken As String
    AccToken = Sheet1.Range("C4").Value
    If AccToken = vbNullString Then
        MsgBox "Please enter your Bitly Access Token to get started" & vbCrLf & "hoi"
        Exit Sub
    End If
    
    Dim LongURL As String
    LongURL = Target.Value
    
    Dim objHTTP As Object
    Set objHTTP = CreateObject("MSXML2.ServerXMLHTTP")
    
    Dim URL As String
    URL = "https://api-ssl.bitly.com/v4/bitlinks"

    objHTTP.Open "POST", URL, False

    objHTTP.setRequestHeader "Authorization", "Bearer " & AccToken
    objHTTP.setRequestHeader "Content-type", "application/json"
    
    Dim Json As String
    Json = "{""long_url"": """ & LongURL & """,   ""domain"": ""bit.ly"",   ""group_guid"": ""account_group_guid""}" 'the group_guid for free bitly accounts is on the url https://app.bitly.com/{group_guid}/bitlinks/
    
    objHTTP.send Json
    
    Dim result As String
    result = objHTTP.responseText
    
    Me.Range("C" & Target.Row).Value = Left(result, Len(result) - 1)
    
    Set objHTTP = Nothing
End If
End Sub


Solution 1:[1]

I think your code should work now. To extractes the value in Excel with the code, it was easier mid(cell with response,72,22) if you use paid bitly it will vary.

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 luisap