'How to check if ssh-agent is already running in bash?
I have a sample sh
script on my Linux environment, which basically run's the ssh-agent
for the current shell, adds a key to it and runs two git commands:
#!/bin/bash
eval "$(ssh-agent -s)"
ssh-add /home/duvdevan/.ssh/id_rsa
git -C /var/www/duvdevan/ reset --hard origin/master
git -C /var/www/duvdevan/ pull origin master
Script actually works fine, but every time I run it I get a new process so I think it might become a performance issue and I might end up having useless processes out there.
An example of the output:
Agent pid 12109
Identity added: /home/duvdevan/.ssh/custom_rsa (rsa w/o comment)
Also, along with all this, is it possible to find an existing ssh-agent
process and add my keys into it?
Solution 1:[1]
No, really, how to check if ssh-agent
is already running in bash?
Answers so far don't appear to answer the original question...
Here's what works for me:
if ps -p $SSH_AGENT_PID > /dev/null
then
echo "ssh-agent is already running"
# Do something knowing the pid exists, i.e. the process with $PID is running
else
eval `ssh-agent -s`
fi
Solution 2:[2]
Also, along with all this, is it possible to find an existing ssh-agent process and add my keys into it?
Yes. We can store the connection info in a file:
# Ensure agent is running
ssh-add -l &>/dev/null
if [ "$?" == 2 ]; then
# Could not open a connection to your authentication agent.
# Load stored agent connection info.
test -r ~/.ssh-agent && \
eval "$(<~/.ssh-agent)" >/dev/null
ssh-add -l &>/dev/null
if [ "$?" == 2 ]; then
# Start agent and store agent connection info.
(umask 066; ssh-agent > ~/.ssh-agent)
eval "$(<~/.ssh-agent)" >/dev/null
fi
fi
# Load identities
ssh-add -l &>/dev/null
if [ "$?" == 1 ]; then
# The agent has no identities.
# Time to add one.
ssh-add -t 4h
fi
This code is from pitfalls of ssh agents which describes both the pitfalls of what you're currently doing, of this approach, and how you should use ssh-ident to do this for you.
If you only want to run ssh-agent if it's not running and do nothing otherwise:
if [ $(ps ax | grep [s]sh-agent | wc -l) -gt 0 ] ; then
echo "ssh-agent is already running"
else
eval $(ssh-agent -s)
if [ "$(ssh-add -l)" == "The agent has no identities." ] ; then
ssh-add ~/.ssh/id_rsa
fi
# Don't leave extra agents around: kill it on exit. You may not want this part.
trap "ssh-agent -k" exit
fi
However, this doesn't ensure ssh-agent
will be accessible (just because it's running doesn't mean we have $SSH_AGENT_PID
for ssh-add
to connect to).
Solution 3:[3]
If you want it to be killed right after the script exits, you can just add this after the eval line:
trap "kill $SSH_AGENT_PID" exit
Or:
trap "ssh-agent -k" exit
$SSH_AGENT_PID
gets set in the eval of ssh-agent -s
.
You should be able to find running ssh-agent
s by scanning through /tmp/ssh-*
and reconstruct the SSH_AGENT
variables from it (SSH_AUTH_SOCK
and SSH_AGENT_PID
).
Solution 4:[4]
ps -p $SSH_AGENT_PID > /dev/null || eval "$(ssh-agent -s)"
Single line command. Run for the first time will start ssh-agent. Run for the second time will not start the ssh-agent. Simple and Elegant Mate !!!
Solution 5:[5]
Using $SSH_AGENT_PID
can only test the ssh-agent
but miss identities when it is not yet added
$ eval `ssh-agent`
Agent pid 9906
$ echo $SSH_AGENT_PID
9906
$ ssh-add -l
The agent has no identities.
So it would be save to check it with ssh-add -l
with an expect script like example below:
$ eval `ssh-agent -k`
Agent pid 9906 killed
$ ssh-add -l
Could not open a connection to your authentication agent.
$ ssh-add -l &>/dev/null
$ [[ "$?" == 2 ]] && eval `ssh-agent`
Agent pid 9547
$ ssh-add -l &>/dev/null
$ [[ "$?" == 1 ]] && expect $HOME/.ssh/agent
spawn ssh-add /home/user/.ssh/id_rsa
Enter passphrase for /home/user/.ssh/id_rsa:
Identity added: /home/user/.ssh/id_rsa (/home/user/.ssh/id_rsa)
$ ssh-add -l
4096 SHA256:XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX /home/user/.ssh/id_rsa (RSA)
So when both ssh-agent
and ssh-add -l
are put to run on a bash script:
#!/bin/bash
ssh-add -l &>/dev/null
[[ "$?" == 2 ]] && eval `ssh-agent`
ssh-add -l &>/dev/null
[[ "$?" == 1 ]] && expect $HOME/.ssh/agent
then it would always check and assuring that the connection is running:
$ ssh-add -l
4096 SHA256:XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX /home/user/.ssh/id_rsa (RSA)
You can also emulate the repeating of commands on above script with do while
Solution 6:[6]
The accepted answer did not work for me under Ubuntu 14.04.
The test to check if the ssh-agent is running I have to use is:
[[ ! -z ${SSH_AGENT_PID+x} ]]
And I am starting the ssh-agent with:
exec ssh-agent bash
Otherwise the SSH_AGENT_PID
is not set.
The following seems to work under both Ubuntu 14.04 and 18.04.
#!/bin/bash
sshkey=id_rsa
# Check ssh-agent
if [[ ! -z ${SSH_AGENT_PID+x} ]]
then
echo "[OK] ssh-agent is already running with pid: "${SSH_AGENT_PID}
else
echo "Starting new ssh-agent..."
`exec ssh-agent bash`
echo "Started agent with pid: "${SSH_AGENT_PID}
fi
# Check ssh-key
if [[ $(ssh-add -L | grep ${sshkey} | wc -l) -gt 0 ]]
then
echo "[OK] SSH key already added to ssh-agent"
else
echo "Need to add SSH key to ssh-agent..."
# This should prompt for your passphrase
ssh-add ~/.ssh/${sshkey}
fi
Solution 7:[7]
I've noticed that having a running agent is not enough because sometimes, the SSH_AUTH_SOCK
variable is set or pointing to a socket file that does not exist anymore.
Therefore, to connect to an already running ssh-agent
on your machine, you can do this :
$ pgrep -u $USER -n ssh-agent -a
1906647 ssh-agent -s
$ ssh-add -l
Could not open a connection to your authentication agent.
$ test -z "$SSH_AGENT_PID" && export SSH_AGENT_PID=$(pgrep -u $USER -n ssh-agent)
$ test -z "$SSH_AUTH_SOCK" && export SSH_AUTH_SOCK=$(ls /tmp/ssh-*/agent.$(($SSH_AGENT_PID-1)))
$ ssh-add -l
The agent has no identities.
Solution 8:[8]
cat /usr/local/bin/ssh-agent-pro << 'EOF'
#!/usr/bin/env bash
SSH_AUTH_CONST_SOCK="/var/run/ssh-agent.sock"
if [[ x$(wc -w <<< $(pidof ssh-agent)) != x1 ]] || [[ ! -e ${SSH_AUTH_CONST_SOCK} ]]; then
kill -9 $(pidof ssh-agent) 2>/dev/null
rm -rf ${SSH_AUTH_CONST_SOCK}
ssh-agent -s -a ${SSH_AUTH_CONST_SOCK} 1>/dev/null
fi
echo "export SSH_AUTH_SOCK=${SSH_AUTH_CONST_SOCK}"
echo "export SSH_AGENT_PID=$(pidof ssh-agent)"
EOF
echo "eval \$(/usr/local/bin/ssh-agent-pro)" >> /etc/profile
. /etc/profile
then you can ssh-add xxxx
once, you can use ssh-agent everytime when you login.
Solution 9:[9]
Regarding finding running ssh-agents, previous answers either don't work or rely on a magic file like $HOME/.ssh_agent
. These approaches require us to believe that user never run agents without saving their output to this file.
My approach instead relies on a rarely changed default UNIX domain socket template to find an accessible ssh-agent
among available possibilities.
# (Paste the below code to your ~/.bash_profile and ~/.bashrc files)
C=$SSH_AUTH_SOCK
R=n/a
unset SSH_AUTH_SOCK
for s in $(ls $C /tmp/ssh-*/agent.* 2>/dev/null | sort -u) ; do
if SSH_AUTH_SOCK=$s ssh-add -l >/dev/null ; then R=$? ; else R=$? ; fi
case "$R" in
0|1) export SSH_AUTH_SOCK=$s ; break ;;
esac
done
if ! test -S "$SSH_AUTH_SOCK" ; then
eval $(ssh-agent -s)
unset SSH_AGENT_PID
R=1
fi
echo "Using $SSH_AUTH_SOCK"
if test "$R" = "1" ; then
ssh-add
fi
In this approach, SSH_AGENT_PID
remains unknown, since it is hard to deduce it for non-roots. I assume it is actually not required for users since they don't normally want to stop agents. On my system, setting SSH_AUTH_SOCK
is enough to communicate with agent for e.g. passwordless authentication.
The code should work with any shell-compatible shell.
Solution 10:[10]
You can modify line #1 to:
PID_SSH_AGENT=`eval ssh-agent -s | grep -Po "(?<=pid\ ).*(?=\;)"`
And then at the end of the script you can do:
kill -9 $PID_SSH_AGENT
Solution 11:[11]
Thanks to all the answers here. I've used this thread a few times over the years to tweak my approach. Wanted to share my current ssh-agent.sh
checker/launcher script that works for me on Linux and OSX.
The following block is my $HOME/.bash.d/ssh-agent.sh
function check_ssh_agent() {
if [ -f $HOME/.ssh-agent ]; then
source $HOME/.ssh-agent > /dev/null
else
# no agent file
return 1
fi
if [[ ${OSTYPE//[0-9.]/} == 'darwin' ]]; then
ps -p $SSH_AGENT_PID > /dev/null
# gotcha: does not verify the PID is actually an ssh-agent
# just that the PID is running
return $?
fi
if [ -d /proc/$SSH_AGENT_PID/ ]; then
# verify PID dir is actually an agent
grep ssh-agent /proc/$SSH_AGENT_PID/cmdline > /dev/null 2> /dev/null;
if [ $? -eq 0 ]; then
# yep - that is an agent
return 0
else
# nope - that is something else reusing the PID
return 1
fi
else
# agent PID dir does not exist - dead agent
return 1
fi
}
function launch_ssh_agent() {
ssh-agent > $HOME/.ssh-agent
source $HOME/.ssh-agent
# load up all the pub keys
for I in $HOME/.ssh/*.pub ; do
echo adding ${I/.pub/}
ssh-add ${I/.pub/}
done
}
check_ssh_agent
if [ $? -eq 1 ];then
launch_ssh_agent
fi
I launch the above from my .bashrc
using:
if [ -d $HOME/.bash.d ]; then
for I in $HOME/.bash.d/*.sh; do
source $I
done
fi
Hope this helps others get up and going quickly.
Created a public gist if you want to hack/improve this with me: https://gist.github.com/dayne/a97a258b487ed4d5e9777b61917f0a72
Solution 12:[12]
I made this bash function to count and return the number of running ssh-agent processes... it searches ssh-agent process using procfs instead of using $ ps -p $SSH_AGENT_PID
:cmd or $SSH_AUTH_SOCK
:var ... (these ENV-var. can still be set with old values while ssh-agent's process is already killed: if $ ssh-agent -k
or $ $(ssh-agent -k)
instead of $ eval $(ssh-agent -k)
)
function count_agent_procfs(){
declare -a agent_list=( )
for folders in $(ls -d /proc/*[[:digit:]] | grep -v /proc/1$);do
fichier="${folders}/stat"
pid=${folders/\/proc\//}
[[ -f ${fichier} ]] && [[ $(cat ${fichier} | cut -d " " -f2) == "(ssh-agent)" ]] && agent_list+=(${pid})
done
return ${#agent_list[@]}
}
..and then if there is a lot of ssh-agent process running you get their PID with this list..."${agent_list[@]}"
Sources
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Source: Stack Overflow