'Laravel route returning error 404 when attempt is made to pass value to controller function
I have a button in my blade like this
@can('customer_show')
<a class = "btn btn-primary" href = "{{ route('admin.loan-applications.showCustView', $loanApplication->user_id) }}">
View Applicant
</a>
@endcan
And this is the route:
Route::get('loan-applications/{loan_application}/showCustView', 'loanApplicationsController@showCust')->name('loan-applications.showCustView');
And in my controller, i did:
public function showCust(LoanApplication $loanApplication)
{
$customerInformation = customerInfoModel::where('Cust_id', $loanApplication->user_id));
return view('admin.loanApplictions.showCustView', compact(['customerInformation', 'loanApplication']));
}
What i am trying to do is fetch the row from the database attached to customerInfoModel where the the Cust_id field equals the loanApplication->user_id of the loan being viewed currently in the blade above. When the button "view Applicant" is hit, i get an error 404 page. Why is that so?
Solution 1:[1]
Check it out the route list using this command
php artisan route:list
//this command will show all the routes in your application
If your route not listed on that route list checkout for routes with same Url on your route manually on routes file.
if you found change the url & use this command to clear cache
php artisan optimize:clear
i have found the comment of you on last answer. check out for route model binding . i think you have to add a
public function showCust( $loanApplicationCustId)
{
$customerInformation = customerInfoModel::where('Cust_id', $loanApplicationCustId))->first();
return view('admin.loanApplictions.showCustView', compact(['customerInformation', 'loanApplication']));
}
It should be like this .. i hope it works for you...... else share your project git repo link
Solution 2:[2]
I think it should be like following:
@can('customer_show')
<a class = "btn btn-primary" href = "{{ route('loan-applications.showCustView', $loanApplication->user_id) }}">
View Applicant
</a>
@endcan
try that
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Zeekstem |
Solution 2 | Alya Al Siyabi |