'sqlalchemy.exc.ArgumentError: Could not parse rfc1738 URL from string
I'm learning flask web microframework and after initialization of my database I run flask db init
I run flask db migrate
, to migrate my models classes to the database and i got an error. I work on Windows 10, the database is MySQL, and extensions install are flask-migrate
, flask-sqlalchemy
, flask-login
.
(env) λ flask db migrate
Traceback (most recent call last):
File "c:\python36\Lib\runpy.py", line 193, in _run_module_as_main
"__main__", mod_spec)
File "c:\python36\Lib\runpy.py", line 85, in _run_code
exec(code, run_globals)
File "C:\Users\aka\Dev\dream-team\env\Scripts\flask.exe\__main__.py", line 9, in <module>
File "c:\users\aka\dev\dream-team\env\lib\site-packages\flask\cli.py", line 513, in main
cli.main(args=args, prog_name=name)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\flask\cli.py", line 380, in main
return AppGroup.main(self, *args, **kwargs)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\click\core.py", line 697, in main
rv = self.invoke(ctx)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\click\core.py", line 1066, in invoke
return _process_result(sub_ctx.command.invoke(sub_ctx))
File "c:\users\aka\dev\dream-team\env\lib\site-packages\click\core.py", line 1066, in invoke
return _process_result(sub_ctx.command.invoke(sub_ctx))
File "c:\users\aka\dev\dream-team\env\lib\site-packages\click\core.py", line 895, in invoke
return ctx.invoke(self.callback, **ctx.params)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\click\core.py", line 535, in invoke
return callback(*args, **kwargs)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\click\decorators.py", line 17, in new_func
return f(get_current_context(), *args, **kwargs)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\flask\cli.py", line 257, in decorator
return __ctx.invoke(f, *args, **kwargs)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\click\core.py", line 535, in invoke
return callback(*args, **kwargs)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\flask_migrate\cli.py", line 90, in migrate
rev_id, x_arg)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\flask_migrate\__init__.py", line 197, in migrate
version_path=version_path, rev_id=rev_id)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\alembic\command.py", line 176, in revision
script_directory.run_env()
File "c:\users\aka\dev\dream-team\env\lib\site-packages\alembic\script\base.py", line 427, in run_env
util.load_python_file(self.dir, 'env.py')
File "c:\users\aka\dev\dream-team\env\lib\site-packages\alembic\util\pyfiles.py", line 81, in load_python_file
module = load_module_py(module_id, path)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\alembic\util\compat.py", line 83, in load_module_py
spec.loader.exec_module(module)
File "<frozen importlib._bootstrap_external>", line 678, in exec_module
File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed
File "migrations\env.py", line 87, in <module>
run_migrations_online()
File "migrations\env.py", line 70, in run_migrations_online
poolclass=pool.NullPool)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\sqlalchemy\engine\__init__.py", line 465, in engine_from_config
return create_engine(url, **options)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\sqlalchemy\engine\__init__.py", line 424, in create_engine
return strategy.create(*args, **kwargs)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\sqlalchemy\engine\strategies.py", line 50, in create
u = url.make_url(name_or_url)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\sqlalchemy\engine\url.py", line 211, in make_url
return _parse_rfc1738_args(name_or_url)
File "c:\users\aka\dev\dream-team\env\lib\site-packages\sqlalchemy\engine\url.py", line 270, in _parse_rfc1738_args
"Could not parse rfc1738 URL from string '%s'" % name)
sqlalchemy.exc.ArgumentError: Could not parse rfc1738 URL from string 'mysql/dt_admin:dt2016@localhost/dreamteam_db'
Solution 1:[1]
You are not using a valid URL in the connection string.
Review the documentation on how the MySQL connection URLs need to be structured: http://docs.sqlalchemy.org/en/latest/dialects/mysql.html.
Depending on the MySQL driver that you use the connection URL is different. For example, if you use pymysql, your URL should be:
mysql+pymysql://<username>:<password>@<host>/<dbname>[?<options>]
Solution 2:[2]
i'd forget the port number to enter the port, this is the URL connection string:
`SQLALCHEMY_DATABASE_URI = 'mysql://dt_admin:dt2016@localhost:3308/dreamteam_db'
it work now, thanks
Solution 3:[3]
make sure that there is no space or newline in the URI string
Solution 4:[4]
URL in the connection string is not valid.
you can check the documentation on how the MySQL connection URLs need to be structured here : http://docs.sqlalchemy.org/en/latest/dialects/mysql.html.
Example syntax for postgresql with psycopg2 driver it look like this :-
sql_alchemy_conn = postgresql+psycopg2://ubuntu@localhost:5432/airflow
Solution 5:[5]
just had to remove the quotes
I was using like that:
sql_alchemy_conn = 'postgresql://user:password@host:port/db'
And this worked:
sql_alchemy_conn = postgresql://user:password@host:port/db
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Miguel Grinberg |
Solution 2 | sylvan kadjo |
Solution 3 | Ahmed El Damasy |
Solution 4 | officialrahulmandal |
Solution 5 | Claudio Shigueo Watanabe |