convert int to ascii - more than one character in rune literal

Question

How do I convert into to its ASCII?

In java it's System.out.println((char)(49)); //gives 1

I tried

a := '42'
fmt.Println(rune(a))

I get more than one character in rune literal

Answer 1

The reason you're getting this error is in this variable:

a := '42'

A byte literal may only contain one character, use this instead;

a := byte(42)

Edit: Use string(a) to get the expected results, like boo said.

Answer 2

Use a string conversion to convert an ASCII numeric value to a string containing the ASCII character:

fmt.Println(string(49)) // prints 1

The go vet command warns about the int to string conversion in the this code snippet because the conversion is commonly thought to create a decimal representation of the number. To squelch the warning, use a rune instead of an int:

fmt.Println(string(rune(49))) // prints 1

Run it on the playground.

This works for any rune value, not just the ASCII subset of runes.

Another option is to create a slice of bytes with the ASCII value and convert the slice to a string.

b := []byte{49}
fmt.Println(string(b))  // prints 1

Run it on the playground

A variation on the previous snippet that works on all runes is:

b := []rune{49}
fmt.Println(string(b))  // prints 1

Answer 3

I suppose to do like this, in a very simple term explaining.

i := 1
fmt.Println("number value", i)

s := strconv.Itoa(i)
fmt.Println("string value", s)

a := []rune(s)[0]
fmt.Println("ascii value", a)

n := string(a)
fmt.Println("back to string value", n)

and output is following:

number value 1
string value 1
ascii value 49
back to string value 1

I know this is not the best one answer, but still it works fine without any issue.

Answer 4

fmt.Printf("%c", 49)