'SQL Server date format yyyymmdd

I have a varchar column where some values are in mm/dd/yyyy format and some are in yyyymmdd.

I want to convert all mm/dd/yyyy dates into the yyyymmdd format. What is the best way to do this? Thanks

Table is Employees and column is DOB



Solution 1:[1]

Assuming your "date" column is not actually a date.

Select convert(varchar(8),cast('12/24/2016' as date),112)

or

Select format(cast('12/24/2016' as date),'yyyyMMdd')

Returns

20161224

Solution 2:[2]

DECLARE @v DATE= '3/15/2013'

SELECT CONVERT(VARCHAR(10), @v, 112)

you can convert any date format or date time format to YYYYMMDD with no delimiters

Solution 3:[3]

try this....

SELECT FORMAT(CAST(DOB AS DATE),'yyyyMMdd') FROM Employees;

Solution 4:[4]

Select CONVERT(VARCHAR(8), GETDATE(), 112)

Tested in SQL Server 2012

https://www.w3schools.com/sql/func_sqlserver_convert.asp

Solution 5:[5]

You can do as follows:

Select Format(test.Time, 'yyyyMMdd')
From TableTest test

Solution 6:[6]

In SQL Server, you can do:

select coalesce(format(try_convert(date, col, 112), 'yyyyMMdd'), col)

This attempts the conversion, keeping the previous value if available.

Note: I hope you learned a lesson about storing dates as dates and not strings.

Solution 7:[7]

SELECT YEAR(getdate()) * 10000 + MONTH(getdate()) * 100 + DAY(getdate())

Solution 8:[8]

mm/dd/yyyy corresponds to U.S. standard so if you convert to date using 101 value and then to varchar using 112 for ISO date get the expected result.

declare @table table (date_value varchar(10))
insert into @table values ('03/30/2022'),('20220330')

select date_value
    --converted to varchar
    ,case 
        --mm/dd/yyyy pattern
        when patindex('[0,1][0-9]/[0-3][0-9]/[0-9][0-9][0-9][0-9]',date_value)>0 then convert(varchar(10),convert(date,date_value,101),112) 
        else date_value end date_value_new
    --converted to date
    ,case 
        when patindex('[0,1][0-9]/[0-3][0-9]/[0-9][0-9][0-9][0-9]',date_value)>0 then convert(date,date_value,101)
        else convert(date,date_value,112) end date_value_date
from @table

Sources

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Source: Stack Overflow

Solution Source
Solution 1 John Cappelletti
Solution 2
Solution 3 Ankitkumar Tandel
Solution 4 rchacko
Solution 5 mishsx
Solution 6 Gordon Linoff
Solution 7 Varun
Solution 8 Borja